Ask question

Ask question

All categories

2 years ago

14

A bar graphs shows that sports books received 9 votes. If the scale is 0 to 20 by twos , where should the bar end for the sports

books

1 answer:

olya-2409 [2.1K]2 years ago

7 0

A little past the 8.

You might be interested in

Can someone please answer. There is only one problem. There's a picture too. Thank you!

amm1812

The answer is 14137.17 because to find the volume of the sphere, the equation is 4/3 times pi times the radius cubed.

3 0

2 years ago

Please help I dont understand

Studentka2010 [4]

Step-by-step explanation:

When it says y varies directly with x it just means that y and x are proportional/equal to each other. The constant of variation and the constant of proportionality are the same thing just different way of saying it so they can confuse you and make your life miserable. Since y and x are proportional to each other and the constant of proportionalty is -5 to make an equation that represents a line you use the formula y=mx+b. That is the slope of the line. With that formula let's first plus in the x so we have y=m2+b. The formula for direct variation is y=kx as well that's good to know and it's good to memorize all these formulas. Math becaomes easier when you have the process down pat and you just need to plug numbers into different equations, expressions, and scenarios. Do m = [y1 - y2] / [x1 - x2] and you'll get the answer.

7 0

2 years ago

Solve the initial value problem where y′′+4y′−21 y=0, y(1)=1, y′(1)=0 . Use t as the independent variable.

igor_vitrenko [27]

Answer:

$y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

Step-by-step explanation:

y′′ + 4y′ − 21y = 0

The auxiliary equation is given by

m² + 4m - 21 = 0

We solve this using the quadratic formula. So

$m = \frac{-4 +/- \sqrt{4^{2} - 4 X 1 X (-21))} }{2 X 1}\\ = \frac{-4 +/- \sqrt{16 + 84} }{2}\\= \frac{-4 +/- \sqrt{100} }{2}\\= \frac{-4 +/- 10 }{2}\\= -2 +/- 5\\= -2 + 5 or -2 -5\\= 3 or -7$

So, the solution of the equation is

$y = Ae^{m_{1} t} + Be^{m_{2} t}$

where m₁ = 3 and m₂ = -7.

So,

$y = Ae^{3t} + Be^{-7t}$

Also,

$y' = 3Ae^{3t} - 7e^{-7t}$

Since y(1) = 1 and y'(1) = 0, we substitute them into the equations above. So,

$y(1) = Ae^{3X1} + Be^{-7X1}\\1 = Ae^{3} + Be^{-7}\\Ae^{3} + Be^{-7} = 1 (1)$

$y'(1) = 3Ae^{3X1} - 7Be^{-7X1}\\0 = 3Ae^{3} - 7Be^{-7}\\3Ae^{3} - 7Be^{-7} = 0 \\3Ae^{3} = 7Be^{-7}\\A = \frac{7}{3} Be^{-10}$

Substituting A into (1) above, we have

$\frac{7}{3}B e^{-10}e^{3} + Be^{-7} = 1 \\\frac{7}{3}B e^{-7} + Be^{-7} = 1\\\frac{10}{3}B e^{-7} = 1\\B = \frac{3}{10} e^{7}$

Substituting B into A, we have

$A = \frac{7}{3} \frac{3}{10} e^{7}e^{-10}\\A = \frac{7}{10} e^{-3}$

Substituting A and B into y, we have

$y = Ae^{3t} + Be^{-7t}\\y = \frac{7}{10} e^{-3}e^{3t} + \frac{3}{10} e^{7}e^{-7t}\\y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

So the solution to the differential equation is

$y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

6 0

3 years ago

HELP ASAP I HATE MATH

Arte-miy333 [17]

Answer:

step attached

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=20°, and CD = 94 feet. Find the length of BC to the nearest tenth of a foot.

kkurt [141]

Answer:

274.8

Step-by-step explanation:

8 0

2 years ago