Answer:
If Raven's monthly payment were $125, the amount of the loan that she is considering taking out would be less than $43,205.56.
Step-by-step explanation:
If you think about it this way it may be more simple. If the APR stays constant then a greater payment will result in a greater loan. The opposite is also true meaning a lesser payment will result in a lesser loan. If the amount Raven pays is greater than $145 then the loan will be greater than $43,205.56. If the amount she pays is less than $145 then the loan will be less than $43,205.56. Of the options, only one of these situations will be present. In my case, the correct option was a payment of $125 will result in a lesser loan than $43,205.56.
If
, then any ordered pair would satisfy the equation.
Since we're not given the ordered pairs, then this is the only information I can give to you.
1. An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force
2. When physicists speak about an object's velocity, they are talking not only about the object's speed but also about the direction in which it's moving. Similarly, force has a directional component as well as a quantitative one -- a force directly opposing an object's velocity has a different effect on the object than a force acting at right angles to its motion. In mathematical terms, force, velocity and acceleration -- which is the rate of change of velocity produced by a force -- are "vector" quantities, which is a term that implies their directional component.
Hope this helps!
Answer:
(x, y) = (1/2, -1)
Step-by-step explanation:
Subtracting twice the first equation from the second gives ...
(2/x +1/y) -2(1/x -5/y) = (3) -2(7)
11/y = -11 . . . . simplify
y = -1 . . . . . . . multiply by y/-11
Using the second equation, we can find x:
2/x +1/-1 = 3
2/x = 4 . . . . . . . add 1
x = 1/2 . . . . . . . multiply by x/4
The solution is (x, y) = (1/2, -1).
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<em>Additional comment</em>
If you clear fractions by multiplying each equation by xy, the problem becomes one of solving simultaneous 2nd-degree equations. It is much easier to consider this a system of linear equations, where the variable is 1/x or 1/y. Solving for the values of those gives you the values of x and y.
A graph of the original equations gives you an extraneous solution of (x, y) = (0, 0) along with the real solution (x, y) = (0.5, -1).
