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FinnZ [79.3K]
3 years ago
13

Please help!

Mathematics
2 answers:
ladessa [460]3 years ago
8 0
Area = length x width
the "big" rectangle: length = 15,  width = 14
the blue rectangle is: length = 15 - 4,  width = 14 - 6

Area of blue rectangle = (15 - 4)(14 - 6)
Answer: D
alekssr [168]3 years ago
7 0

Answer:

its d and your hot

Step-by-step explanation:

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You roll fair6-sided die what is P(roll a 2)?
creativ13 [48]

Answer:

1/6

Step-by-step explanation:

It is a 6 sided die, so you have 6 possibilities, so that is going to be you denominator.

There is only one number 2 on the die, so you have 1 as your numerator.

5 0
4 years ago
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A dozen apple costs $2.55.at this rate how much would 8 apple cost?
vladimir2022 [97]
12=2.55 how about 8
8 x 2.55 divided by 12=$1.7
8 0
3 years ago
If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)
Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

\log_dabc=\log_da+\log_db+\log_dc

Then using the change of base formula, we can derive the relationship

\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}

This immediately tells us that

\log_dc=\dfrac1{\log_cd}=\dfrac12

Notice that none of a,b,c,d can be equal to 1. This is because

\log_1x=y\implies1^{\log_1x}=1^y\implies x=1

for any choice of y. This means we can safely do the following without worrying about division by 0.

\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}

so that

\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23

Similarly,

\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}

so that

\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34

So we end up with

\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}

###

Another way to do this:

\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}

\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}

\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12

Then

abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}

So we have

\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}

4 0
3 years ago
A blank is a unit rate with a denominator of one unit
exis [7]

the answer is rate hope it helps


6 0
3 years ago
Algebra 1 -5c+d=2c find for c
beks73 [17]

Answer:

d/7 = c

Step-by-step explanation:

-5c+d=2c

Add 5c to each side

-5c+5c+d=2c+5c

d = 7c

Divide each side by 7

d/7 = 7c/7

d/7 = c

8 0
3 years ago
Read 2 more answers
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