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3 years ago

Using a System to Break Even

Mathematics

1 answer:

andreev551 [17]3 years ago

8 0

Answer: P^2 - 10p + 24 = 0

Step-by-step explanation:

Given that a company’s weekly revenue, in thousands, is modeled by the equation

R = -p2 + 14p,

where p is the price of the product it makes. The company is considering hiring an outside source to distribute its products, which will cost the company 4p + 24 thousand dollars per week.

If the company want to break even, the cost of hiring distributors will be equal to the revenue per week.

Therefore,

-P^2 + 14p = 4p + 24

Collect the like terms

-P^2 + 14p - 4p - 24 = 0

-P^2 + 10p - 24 = 0

Multiply all by minus sign

P^2 - 10p + 24 = 0

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18) The perimeter of a regular hexagon with side 'k' units is *

Travka [436]

Answer:

perimeter of a regular hexagon=6×side length

side length in question is 'k'

perimeter=6×k=6k

8 0

3 years ago

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

3 years ago

What is 263 divided by 26?

Lilit [14]

Answer:

Step-by-step explanation:

You can put this in the calculator so its easier for you. Have a good day

3 0

2 years ago

Solve for b.<br> 17 = b/3+13

alina1380 [7]

well it would be 17=1/3+13

7 0

3 years ago

Read 2 more answers

What is the height of a rectangular prism that has a volume of 192 cubic feet and a base with an area of 48 square feet? Explain

Harman [31]

The formula for volume is length × width × height, so this is the same as area of cross section × height. So, if the base of the rectangular prism (the cross section) has an area of 48 square feet, then 48 × the height = 192 cubic feet. Working backwards, we can find out the height (h will stand for height):
48×h=192
h=192÷48
h=4
Therefore, the height of the rectangular prism is 4 feet

6 0

4 years ago