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3 years ago

A 10 ounce container if milk contains 200 calories. how many calories does each ounce of milk contain?

Mathematics

1 answer:

kaheart [24]3 years ago

5 0

The answer that is correct is 20 so there you go

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Seven times a number plus the number is 24. what is the number

katrin2010 [14]

Answer:

x=3 is the number

Step-by-step explanation:

Suppose number be "x".

Equation will be

7x + x = 24

8x = 24

x = 24/8

x = 3

5 0

3 years ago

Read 2 more answers

Kareendeep has $168.50 in her bank account. She buys x shirts for $5.5o each. Write and solve an equation Kareendeep can use to

Vikentia [17]

Answer:

Equation: 5.5x = 168.5

Solution: 30 shirts

Step-by-step explanation:

First, create the equation where x is the number of shirts.

Since each shirt is $5.50, the cost of the shirts will be 5.50x

Set this equal to 168.50, since that is how much money Kareendeep has.

So, the equation will be 5.5x = 168.5

Now, solve this for x, the number of shirts she can buy:

5.5x = 168.5

Divide each side by 5.5

x = 30.6

Since we can only have a whole number of shirts, she can only buy 30 shirts.

So, the answer is 30 shirts.

5 0

3 years ago

Solve y=f(x) for x. Then find the input when the output is -3.

DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:\left(x-5\right)^3-1$

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

$\:\:y=\:\left(x-5\right)^3-1$

$-3\:=\:\left(x-5\right)^3-1\:\:\:$

switch sides

$\left(x-5\right)^3-1=-3$

Add 1 to both sides

$\left(x-5\right)^3-1+1=-3+1$

$\left(x-5\right)^3=-2$

$\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

Thus, the input values are:

$x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}$