Let s and g represents the numbers of suits and gowns produced.
The number of zippers used is 2s+g.
The number of buttons used is 5s+8g.
In order to use all of the available zippers and buttons, we must have ...
- 2s + g = 171
- 5s + 8g = 576
Cramer's rule tells you the solution to the system
Is given by
- x = (bf-ey)/(bd-ea)
- y = (cd-fa)/(bd-ea)
Using this rule on the equations for zippers and buttons, we have
... s = (1·576 -8·171)/(1·5 -8·2) = -792/-11 = 72
... g = (171·5 -2·576)/-11 = -297/-11 = 27
72 suits and 27 gowns can be made from available zippers and buttons.
Answer:
m = 11/9
Step-by-step explanation:
m = (y2 - y1) / (x2 - x1)
= (-7 - 4) / (-3 - 6)
= -11/-9
= 11/9
Answer:
154,897
Step-by-step explanation:
Labradors were
6997 MORE than 15 TIME Danes
So, first, what is 15 times Danes??
Given 9860 Danes, fifteen times Danes would be:
9860 * 15 = 147,900
Now, 6997 MORE to that, it would be:
147,900 + 6997 = 154,897
Thus,
There were 154,897 registered Labrador Retrievers
7x + 15 = 38
7x = 38 - 15
7x = 23
x = 23/7 (twenty- three sevenths)
Answer:
After 11 weeks, Darnell′s savings account will have a total of $8,360.
Step-by-step explanation:
The data provided is as follows:
n: 1 2 3 4
f (n): 260 360 460 560
Consider the data for f (n).
The series f (n) follows an arithmetic sequence with a common difference of 100 and first term as 260.
The nth term of an arithmetic sequence is:
![a_{n}=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=a_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Compute the value of f (11) as follows:
![f(11)=\frac{11}{2}[(2\times260)+(11-1)\times 100]](https://tex.z-dn.net/?f=f%2811%29%3D%5Cfrac%7B11%7D%7B2%7D%5B%282%5Ctimes260%29%2B%2811-1%29%5Ctimes%20100%5D)
![=5.5\times[520+1000]\\\\=5.5\times 1520\\\\=8360](https://tex.z-dn.net/?f=%3D5.5%5Ctimes%5B520%2B1000%5D%5C%5C%5C%5C%3D5.5%5Ctimes%201520%5C%5C%5C%5C%3D8360)
Thus, after 11 weeks, Darnell′s savings account will have a total of $8,360.
