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KATRIN_1 [288]
2 years ago
13

Nora knit a total of 10 centimeters of scarf over 5 nights. After 6 nights of knitting, how many centimeters of scarf will Nora

have knit in total? Solve using unit rates.
Mathematics
1 answer:
Anon25 [30]2 years ago
7 0

Answer:

Step-by-step explanation:

10 ÷ 5 = 2 x6 = 12

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What is the derivative of 2te^-t
Sveta_85 [38]
(2te^{-t})'=(2t)'e^{-t}+2t(e^{-t})'=2e^{-t}+2t(-e^{-t})=2e^{-t}-2te^{-t}
6 0
3 years ago
How do u solve for x please and thank you!! Need ASAP
gavmur [86]

Answer:

Step-by-step explanation:

both sides are the same length so 20+6x+3=18+7x+2

all you have to do is get the variables and non-variables on opposite sides of the equation so 3=x

5 0
3 years ago
I have 18 ones,15 hundreds,15 tens,and 8 thousands.what number am i?
antoniya [11.8K]
15818 ?? This is making me get a headache
3 0
3 years ago
Please answer these questions!!!!!! Fast!!!!!!
vodka [1.7K]

Answer:

For an object of mass M and velocity V, the kinetic energy is written as:

K = (M/2)*V^2

And also remember that:

1 J = 1 kg*m/s

a) we know that:

Mass = M = 0.7 kg

Velocity = V = 60 m/s

Then the kinetic energy is:

K = (0.7kg/2)*(60m/s)^2 = 1,260 J

b) We know that in a closed system, the energy is conserved.

This means that if we hit an object with an energy E, the maximum energy that we can give to that object is E.

Then if we have a bat of mass M = 2kg, and velocity V = 30m/s

The kinetic energy of the bat (before hitting the ball) is:

K = (2kg/2)*(30m/s)^2 = 900 J

Obviously, this will never happen, because after we hit the ball the bat keeps moving for a bit, meaning that it still has some kinetic energy and it did not transfer all of the kinetic energy to the ball. But we can not have a more precise estimation, because we do not know the mass of the ball and a lot of other needed information, so we can conclude that, the theoretical maximum energy that could be given to the ball, is 900 J.

c) Here we have:

Mass = M = 1950 kg

Velocity = V = 10 m/s

then the energy is:

K = (1950kg/2)*(10 m/s)^2 = 97,500 J.

d) Notice that in the equation of the kinetic energy we have the velocity squared, which means that the contribution of the velocity is larger than the contribution of the mass.

Then the option with the largest velocity most likely would have the largest kinetic energy, then the correct option is the second counting from the top, with a kinetic energy equal to:

K = (0.25 kg/2)*(50m/s)^2 = 312.5 J.

5 0
3 years ago
If (x, y) = (3, 4) is a solution of the simultaneous equations.
Vinvika [58]
The first thing you want to do is plug in x and y into both equations:

a(3) + b(4) = 4

b(3) + a(4) = 8

rearrange to line up a’s and b’s

3a + 4b = 4

4a + 3b = 8

now you want to choose a or b and multiply each equation by a number to make them have the same amount of a’s or b’s.

4(3a + 4b = 4) = 12a + 16b = 16

3(4a + 3b = 8) = 12a + 9b = 24


Now we subtract the bottom equation from the top and solve for b:

12a + 16b - (12a + 9b) = 16 - 24

7b = -8

b = -8/7


Now we plug back in for b to one of the original equations:

3a + 4(-8/7) = 4

3a + (-32/7) = 4

3a - (32/7) = 4

3a = 4 + (32/7)

3a = (28/7) + (32/7)

3a = 60/7

a = (60/7)/3 = 20/7.


Finally, plug a and b in together to double check using the second equation.

4a + 3b = 8

4(20/7) + 3(-8/7) = ?

(80/7) - (24/7) = ?

56/7 = 8.
4 0
3 years ago
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