Answer:
The critical value for a 98% CI is z=2.33.
The 98% confidence interval for the mean is (187.76, 194.84).
Step-by-step explanation:
We have to develop a 98% confidence interval for the mean number of minutes per day that children between the age of 6 and 18 spend watching television per day.
We know the standard deveiation of the population (σ=21.5 min.).
The sample mean is 191.3 minutes, with a sample size n=200.
The z-value for a 98% CI is z=2.33, from the table of the standard normal distribution.
The margin of error is:
With this margin of error, we can calculate the lower and upper bounds of the CI:
The 98% confidence interval for the mean is (187.76, 194.84).
There was a 20% decrease. To find the decrease, subtract the old number from the new number. (30-24=6) Then divide the decrease (6) by the original number and multiply the answer by 100. (6/30=0.2 0.2*100=20).
Notice, you've got a diameter in inches
and a linear velocity in miles
thus, you'd need to convert first
now, whatever that is, you'll need to divide it by a revolution, recall, a revolution is
thus
Cashier job pays $9 per hour
Delivering newspaper pays $8 per hour
Answer:
y=-6/5x-2.6
Step-by-step explanation: