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2 years ago

If she can skip 300 feet in 20 seconds how far could she skip per second

Mathematics

2 answers:

elena55 [62]2 years ago

5 0

300/20 = 15

she can skip 15 feet per second

hope this helps

liubo4ka [24]2 years ago

4 0

Divide the number of feet by the number of seconds.

300/20= 15

She can skip 15 feet per second.

I hope this helps!

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A four foot tall girl cast a shadow of 6 feet. A shade tree cast a shadow of 24feet. What is the height of the tree?

aleksandr82 [10.1K]

The answer is 16.
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5 0

2 years ago

What is the distance between (6, 1) and (1, -9)?

AVprozaik [17]

Answer: √15 units

Step-by-step explanation:

Let (6,1) be (x^1,y^1) and (1,-9) be (x^2,y^2) .

As we know ,

Distance(D) = √(x^1-x^2) +(y^1-y^2)

Now,

D= √(x^1-x^2) +(y^1-y^2)

= √(6-1) +(1+9)

= √5+10

= √15 units

: Therefore the distance between (6,1) and (1,-9) is √15 units.

4 0

2 years ago

Okay sorry about the other one

Neporo4naja [7]

Number ten is 60 73+36=108

6 0

3 years ago

Brad earns $12.75/hr and works 40 hours a week. What is his gross annual income?

Mrac [35]

$12.75/hr x 40hrs = $510

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3 years ago

Professor York randomly surveyed 240 students at Oxnard University and found that 150 of the students surveyed watch more than 1

BaLLatris [955]

Answer:

1727 students

Step-by-step explanation:

Here we have the formula for sample size given as

$n = \frac{p(1-p)z^2}{ME^2}$

Where:

p = Mean

ME = Margin of error = 3

z = z score

Therefore, we have

p = 150/240 = 0.625

z at 99 % = 2.575

ME = $\pm$ 3%

Therefore $n = \frac{0.625(1-0.625)2.575^2}{0.03^2} = 1726.73$

The number of students Professor York have to sample to estimate the proportion of all Oxnard University students who watch more than 10 hours of television each week within ±3 percent with 99 percent confidence = 1727 students.

5 0

3 years ago