Cotx = Cosx/sinx
1/Cotx = sinx/cosx
Sinx + cosx *1/cotx = sinx + cosx * sinx/cosx = 2sinx
Answer:
3.5 inches
Step-by-step explanation:
create a proportion:
inches / miles = inches / miles
let 'x' = distance in inches
<u>1/4</u> = <u> x </u>
18 252
18x = 252(1/4)
18x = 63
x = 63 / 18
x = 3.5
Answer:
56x + 34
Step-by-step explanation:
12(3 + 5x) + 1/4(16x - 8)
First, use the distributive property. You will get:
(12)(3) + (12)(5x) + (1/4)(16x) - (1/4)(8)
Next, multiply the numbers. You will then have:
36 + 60x + 4x - 2
Now, rearrange the numbers. The variables go in the front. This is what it should look like:
60x + 4x + 36 - 2
Add 60x and 4x, then subtract 36 and 2. This is your answer:
56x + 34
Answer:
The answer would be A
Step-by-step explanation:
Both congruent sides are pairs
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
40 metres covered in 6 seconds
Max speed attained after 6seconds
75 meters covered after 11 seconds
Average Speed for first 40 meters :
Speed = distance / time
Speed = 40m / 6s
Speed = 6.67m/s
To obtain the maximum speed :
Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds
Speed at this point is maximum :
Hence, maximum speed = (35m / 5s) = 7m/s
Suppose, Manuel runs for an additional z seconds after reaching max speed :
Distance from starting line 6+z seconds after race started?
Distance after 6 seconds = 40 metres
Distance after z seconds = 7 * z
Total distance = (40 + 7z)
What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?
Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))
40 + 7(x - 6)
