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liraira [26]
2 years ago
13

Help please !!!! !!!!!

Mathematics
1 answer:
mojhsa [17]2 years ago
4 0

Answer:

Step-by-step explanation:

(5x)^3 ⋅ (3/10)x^(-5) = 5^3⋅x^3 ⋅ (3/(2⋅5)x^(-5)

= 5^(3-1)x^(3-5)(3/2)

= 5^2x^(-2)(3/2)

= (75/2)x^(-2)

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Charlie saves $21.45 each month for 6 months.In the seventh month, he only saves $10.60.How much money will Charlie have after 7
Tomtit [17]
$21.45 x 6 = $128.7
$128.7 + $10.60 = $139.3

Charlie will have saved $139.3 in 7 months
8 0
3 years ago
Please help me! Math
erastova [34]
A. 3/2
b.0.5
c.you have to add them
3 0
3 years ago
Find the midpoint of the segment with the following endpoints (-10,-1) and (-6,7)
Gala2k [10]

Answer:

(-8 , 3)

Step-by-step explanation:

(x1 , y1)   (x2 , y2) = (-10 , -1) (-6 , 7)

\frac{-6-10}{2} ,  \frac{7-1}{2}   -6 is going to be my x1 and -10 my y1

                     7 is going to be my x2 and -1 my y2

(-8 , 3)

7 0
3 years ago
What is the answer to the problem 1-(-18)
Tamiku [17]

Answer:

19

Step-by-step explanation:

1-(-18)

=1+18

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6 0
3 years ago
You are studying the relationship between the history of early childhood trauma (categorized as trauma/no trauma) and weight in
jeka57 [31]

Answer:

You can decide to <u>reject</u> the Null Hypothesis at p < 0.05.

Step-by-step explanation:

In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.

The categories of childhood trauma are:

Trauma and No trauma.

So, number of rows is, <em>r</em> = 2.

The categories of weight in adulthood are:

Low to normal, Overweight, and Obese

So, number of columns is, <em>c</em> = 3.

The distribution of the statistic \chi^{2} is chi-square with (<em>r </em>- 1)(<em>c </em>- 1) degrees of freedom, where <em>r</em> represents the number of rows in the two-way table and <em>c</em> represents the number of columns.

Compute the degrees of freedom as follows:

df = (r-1)(c-1)=(2-1) \times (3-1) = 2

It is provided that the calculated value of Chi-square test statistic is 18.26.

Compute the <em>p</em>-value of the test as follows:

p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011

Decision rule:

The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level.

The significance level is, <em>α</em> = 0.05.

<em>p</em>-value = 0.00011 < <em>α</em> = 0.05.

The null hypothesis will be rejected at 5% level of significance.

Thus, the complete statement is:

"You can decide to <u>reject</u> the Null Hypothesis at p < 0.05."

4 0
3 years ago
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