There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
Answer:
∠L = 43°
∠M = 121°
∠N = 16°
Step-by-step explanation:
<u>Start by setting all sides equal to 180</u>
3x - 5 + 7x + 9 + x = 180
<u>Add like terms</u>
11x + 4 = 180
<u>Solve for x</u>
11x + 4 = 180
- 4 - 4
11x = 176
/ 11 /11
x = 16
<u>Now, plug in 16 for all instances of x on the triangle and solve.</u>
∠L = 43°
∠M = 121°
∠N = 16°
A) yes
B) yes
C) no
For each of these, substitute the value of x in the ordered pair into x in the function.
For A, x = -5; -5<2, so the piece of the function we want is f(x) = 3. In our ordered pair, y=f(x)=3, so yes, it is a solution.
For B, x = 2; 2≤2<6, so the piece of the function we want is f(x) = -x+1. In our ordered pair, y=f(x)=-1; -2+1=-1, so yes, it is a solution.
For C, x = 8; 8≥6, so the piece of the function we want is f(x) = x. In our ordered pair, y=f(x)=-7; -7≠8, so no, it is not a solution.
15-9= 6 the difference is 6 people. i hope this is what you were looking for.
