Draw a diagram to illustrate the problem as shown below.
Let v = speed of the westbound car, mph
Because the eastbound car travels 4 mph faster than the westbound car, its speed is (v+4) mph.
After 2 hours,
the westbound car travels 2v miles west, and the eastbound car travels 2(v+4) miles east.
Because they become separated by 208 miles, therefore
2v + 2(v+4) = 208
4v + 8 = 208
4v = 200
v = 50 mph
The westbound car travels at 50 mph.
The eastbound car travels at v+4 = 54 mph
Answer: The eastbound car travels at 54 mph.
FOR Y
opposite angles - equal
angles in a quadrilateral are 360 degrees
68 + 68 = 136
360 - 136 = 224
224/2 = 112 degrees
angles on a straight line = 180 degrees
180 - 112 = 68
Y = 68
FOR X
angles on a straight line are 180 degrees
180 - 68 = 112 degrees
X=112 degrees
Answer:
Direct & Inverse Proportion (H) - Version 2 January 2016 . A collection of 9-1 Maths GCSE Sample and Specimen questions from AQA, . 1. 2. Write an expression for y in terms of x. [4]. 2. A pebble is thrown vertically upwards. . (b) Find the initial speed of the pebble if the maximum height reached is 16 m. . T is given by.
Answer:
13402
Step-by-step explanation:
PV= $299,132
I/YR= 4.48% or 0.0448
N= 216
PMT= $13402
(Excel works great with this and will solve it for you, use the PMT function and insert the numbers provided. It will show a (-) but that is because a positive PV is placed.)
Step-by-step explanation:
To find quadrilateral's you need to find shapes with edges.
<h2>Quadrilateral's:</h2>
Square
Rectangle
Isosceles Trapezoid