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sveticcg [70]
3 years ago
13

Help asap! will mark brainliest lots of points! 9 minuets

Mathematics
2 answers:
laiz [17]3 years ago
8 0

Answer:

The area of the grass = 2187 square ft

Step-by-step explanation:

∵ The dimension of the yard are 80 ft. and 45 ft.

∴ The area of the rectangle = 80 × 45 = 3600 square ft.

∵ The diameter of the pool is 60 ft.

∴ The area of the semi circle = \frac{1}{2}\pi(30)^{2}=1413 square ft.

∴ The area of the grass = 3600 - 1413 = 2187 square ft

Oxana [17]3 years ago
6 0

Answer:

Rectangle = 3600 ft^2

Semicircle = 1413.72 ft^2

Grass = 2186.28 ft

Step-by-step explanation:

The area of the rectangle is

A = l*w  where l = 45 and w = 80

A = 45*80

   3600 ft^2

We then need to find the area of a circle

A = pi r^2

The radius is 1/2 d

r = 1/2 (60)

r = 30

The area of a circle is pi r^2, but we only have 1/2 of the cirlce so we take 1/2 of the area

1/2A = 1/2 pi (30)^2

  =   1/2 pi *900

      450 pi

   =1413.72 ft^2

The difference is the area we have to cover

rectangle - semicircle

3600 ft^2 - 1413.72

2186.28 ft

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Answer:

\dfrac{AP}{PC}=\dfrac{3}{5}

\dfrac{BN}{CN}=\dfrac{3}{5}

Step-by-step explanation:

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\dfrac{AM}{AD}=\dfrac{AP}{AC}\\ \\\dfrac{3x}{3x+5x}=\dfrac{AP}{AC}\\ \\\dfrac{AP}{AC}=\dfrac{3}{8}\Rightarrow AP=\dfrac{3}{8}AC\\ \\PC=AC-AP=AC-\dfrac{3}{8}AC=\dfrac{5}{8}AC,

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\dfrac{AP}{PC}=\dfrac{\frac{3}{8}AC}{\frac{5}{8}AC}=\dfrac{3}{5}

Consider triangles ACB and PCN. In these triangles,

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Hence, triangles ACB and PCN are similar by AA similarity theorem.

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\dfrac{BN}{CN}=\dfrac{\frac{3}{8}BC}{\frac{5}{8}BC}=\dfrac{3}{5}

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