Answer:
180
Step-by-step explanation:
The answer is 5.23 ft/second
The way I got this answer was first finding the circumference of the merry-go-round using the equation

, where r represents the radius, which is the distance from the center of a circle.
So your equation should look like this

. I used the rounded term of 3.14 for

Once you multiply those terms, you should get the answer, 31.4. Now this is the total distance around the merry-go-round in feet. So, if it takes 6 seconds to make a full rotation and we are trying to find the amount offeet traveled in one second, we should divide the circumference (31.4) by 6 to give us our answer.
So, 31.4÷6=5.2333...ft/second
And I rounded the answer to the nearest hundredth to get 5.23 feet/second
Can you take a pic of the problem?
Answer:
The pencil marks on your page show you exactly how to do that.
Step-by-step explanation:
Take advantage of two rules of exponents:
![\sqrt[n]{x}=x^{\frac{1}{n}}\\\\x^{-n}=\dfrac{1}{x^{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5C%5C%5C%5Cx%5E%7B-n%7D%3D%5Cdfrac%7B1%7D%7Bx%5E%7Bn%7D%7D)
![(d)\quad x^{\frac{-1}{5}}=\dfrac{1}{x^{\frac{1}{5}}}=\dfrac{1}{\sqrt[5]{x}}\\\\(h)\quad x^{\frac{-2}{11}}=\dfrac{1}{x^{\frac{2}{11}}}=\dfrac{1}{\sqrt[11]{x^{2}}}](https://tex.z-dn.net/?f=%28d%29%5Cquad%20x%5E%7B%5Cfrac%7B-1%7D%7B5%7D%7D%3D%5Cdfrac%7B1%7D%7Bx%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%7D%3D%5Cdfrac%7B1%7D%7B%5Csqrt%5B5%5D%7Bx%7D%7D%5C%5C%5C%5C%28h%29%5Cquad%20x%5E%7B%5Cfrac%7B-2%7D%7B11%7D%7D%3D%5Cdfrac%7B1%7D%7Bx%5E%7B%5Cfrac%7B2%7D%7B11%7D%7D%7D%3D%5Cdfrac%7B1%7D%7B%5Csqrt%5B11%5D%7Bx%5E%7B2%7D%7D%7D)