Answer: Translation: The school will build a fast soccer field that is 120m long and 60m wide, but around it there will be an 8m wide race track. Find the area of the terrain and the area of the track
Step-by-step explanation:
Answer:
about 252.78 ft
Step-by-step explanation:
Define angle QMP as α. Then ...
MN = 60·sin(α)
NP = 60·cos(α)
area MPN = (1/2)(MN)(NP) = 1800sin(α)cos(α)
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PQ = 60tan(α)
area MPQ = (1/2)(MP)(PQ) = 1800tan(α)
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The ratio of areas is 2.5, so we have ...
1800tan(α) = 2.5·1800sin(α)cos(α)
1 = 2.5cos(α)² . . . . . . divide by 1800tan(α)
cos(α) = √0.4 . . . . . . solve for cos(α)
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Then the perimeter is ...
Perimeter = MN +NP +PQ +QM = 60sin(α) +60cos(α) +60tan(α) +60/cos(α)
= 60(sin(α) +cos(α) +tan(α) +sec(α))
= 60(0.774597 +0.632456 +1.224745 +1.581139)
= 60(4.212936) = 252.776
The perimeter of the trapezoid is about 252.776 feet.
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With perhaps a little more trouble, you can find the exact value to be ...
perimeter = (6√10)(7+√6+√15)
Answer:
88
Step-by-step explanation:
PEMDAS
9*(6+7-3)-2
1) 6+7=13
13-3=10
9*10-2
2)9*10= 90
3)90-2= 88
Answer:
10
Step-by-step explanation:
P(black bean soup) = cans of black bean / total = 6/12 =1/2
out of the next 20
20 *P(black bean)
20 * 1/2 = 10
900,000 because that is where the value of 9 is placed in the number.