Answer:
a. 3.2 cm
b. 6.25 km
Step-by-step explanation:
a.
(4 km)/(5 km) = 0.8
4 km is 0.8 of 5 km, so in the map it is 0.8 of 4 cm.
0.8 * 4 cm = 3.2 cm
Answer: 3.2 cm
b.
(5 cm)/(4 cm) = 1.25
5 cm is 1.25 times 4 cm, so it represents 1.25 * 5 km.
1.25 * 5 km = 6.25 km
Answer: 6.25 km
Answer : B x 1 2 3 4 y 3.2 6.4 9.6 12.8
WE analyze the first option A
x -- y -- Difference
8 -- 20
9 -- 22.5 -- 2.5
10 -- 25 -- 2.5
11 -- 27.5 -- 2.5
From the first function we can see there is a constant difference of 2.5.
We analyze the second option B
x -- y -- Difference
1 -- 3.2
2 -- 6.4 -- 3.2
3 -- 9.6 -- 3.2
48 -- 12.8 -- 3.2
From the second function we can see there is a constant difference of 3.2
3.2 is the greatest
So second function B has the greatest constant of variation.
<h3>Solution(s):</h3>
<u>1)</u><u> What distance did a car travel that went 70 mph for 6 hours?</u>
Given:
<u>Multiply the RHS by 6 to see what distance was covered by the car in 6 hours.</u>
- 70 miles = 1 hour
- => 70 x 6 miles = 6 hours
- => 420 miles = 6 hours
The car traveled 420 miles in 6 hours.
<u>2)</u><u> What is the perimeter of a rectangle with a length of 7 cm and a width of 4 cm?</u>
Given:
- Length: 7 cm
- Breadth: 4 cm
Formula to find perimeter: 2(L) + 2(B)
<u>Substitute the values into the formula to find the perimeter.</u>
- 2(L) + 2(B)
- => 2(7) + 2(4)
- => 14 + 8
- => 22 cm
The perimeter of the rectangle is 22 cm.
Answer:
;-;
Step-by-step explanation:
Answer:
The 90% confidence interval for the true mean lifespan of this product is between 13.1 and 16.9 years.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 50 - 1 = 49
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 1.6766
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 15 - 1.9 = 13.1 years
The upper end of the interval is the sample mean added to M. So it is 15 + 1.9 = 16.9 years
The 90% confidence interval for the true mean lifespan of this product is between 13.1 and 16.9 years.
