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3 years ago

11

If Figure E is multiplied by a scale factor of 2.5, reflected over the y-axis, and translated 1 unit right and 4 units up, which

is true about E′?

2 answers:

aleksley [76]3 years ago

5 0

Answer is A

E′ has the same shape but not the same size as Figure E.

EastWind [94]3 years ago

4 0

Answer: A

Step-by-step explanation:

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Somebody please help.

Rina8888 [55]

Hey, what do you need help with ?

8 0

2 years ago

Read 2 more answers

Kevin had a total of $320 to spend while shopping. He had spent $156 on video games. He wants to buy caps that are on sale for $

zloy xaker [14]

Maximum number of caps that Kevin can buy is 10.

Solution:

Total money for shopping = $320

Amount spent for video game = $156

Remaining amount that Kevin had = $320 – $156

= $164

Cost of each cap including tax = $15

$\text{Number of caps can buy }=\frac{\text { Remaining amount that Kevin had }}{\text { cost of each cap }}$

$$=\frac{164}{15}$

$$=10\frac{14}{15}$

Maximum number of caps that Kevin can buy is 10.

8 0

3 years ago

HELP ME PLEASE!!!!!!

Eva8 [605]

I realise this is quite late but in case you still wanted the answer, the width is 3m.

If the length is 3m longer than the width, you can write the width as x and the length as x + 3. The perimeter would be both lengths and both widths added together, so you would just write it as:
x + x + x + 3 + x + 3 = 18
4x + 6 = 18
- 6
4x = 12
÷ 4
x = 3

I hope this helps!

4 0

3 years ago

The students at underwood high school are building the shape below to put on their school what is the total area of the shape in

Gennadij [26K]

Answer:

40

Step-by-step explanation:

area= length times width

1 times 10= 10 times 2= 20

2 times 10=20

20+20=40

8 0

3 years ago

A vacant lot is being converted into a community garden. The garden and and a walkway around its perimeter have an area of 460 s

mariarad [96]

Answer:

The width of the walkway is 4 feet.

Step-by-step explanation:

The garden and a walkway around its perimeter have an area of 460 square feet.

The length of the garden = 15 feet

The width of the garden = 12 feet

Assuming that walkway is of uniform width, we can solve the following equation.

$(12+2x)\times(15+2x)= 460$

Expanding this we get;

$4x^{2}+54x+180=460$

$=> 4x^{2}+54x-280=0$

We will solve this using quadratic equation formula:

$x=\frac{-b\pm \sqrt{b^{2} -4ac} }{2a}$

Here a = 4 , b = 54 , c = -280

We get the roots as x = 4 and x = $-\frac{35}{2}$

Neglecting the negative value, we will take x = 4 feet.

Hence, the width of the walkway is 4 feet.

5 0

2 years ago