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3 years ago

Help quick 16 points

Mathematics

1 answer:

aalyn [17]3 years ago

3 0

Answer:

124 child tickets, and 78 adult tickets

Step-by-step explanation:

x=child

y= adult

x+y=202

10x+6y=1708

Multiply eq1 by 6

6x+6y=1212

-4x=-496

x=124

y=78

Hope this helps plz mark brainliest :D

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vampirchik [111]

P = 8B + 4R + 25 <== ur equation

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4 years ago

Please help . I’ll mark you as brainliest if correct!

notka56 [123]

Answer:

the answers are correct what do you need help with?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

In a previous exercise we formulated a model for learning in the form of the differential equation dP dt = k(M − P) where P(t) m

GalinKa [24]

Answer:

$\frac{dP}{M-P}= kdt$

And we can integrate both sides of the equation using the following substitution:

$u= M-P, du =-dP$

And replacing we got:

$\int -\frac{du}{u} = kt +C$

$-ln (u)= kt+c$

If we multiply both sides by -1 we got:

$ln (u ) = -kt -c$

$ln (M-P) = -kt -c$

And using exponential in both sides of the equation we got:

$M-P = e^{-kt} e^{-c}$

And solving for P we got:

$P(t) = M- e^{-kt}e^{-c}$

And replacing $P_o =e^{-c}$ we got:

$P(t) = M - P_o e^{-kt}$

We can use the condition $P(0)=0$ and we got:

$0 = M -P_o e^0$

And we see that $M = P_o$ and replacing we got:

$P= M(1- e^{-kt})$

Step-by-step explanation:

For this case we aasume the following differential equation:

$\frac{dP}{dt}= k(M-P)$

Is a separable differential equation so we can do the following procedure:

$\frac{dP}{M-P}= kdt$

And we can integrate both sides of the equation using the following substitution:

$u= M-P, du =-dP$

And replacing we got:

$\int -\frac{du}{u} = kt +C$

$-ln (u)= kt+c$

If we multiply both sides by -1 we got:

$ln (u ) = -kt -c$

$ln (M-P) = -kt -c$

And using exponential in both sides of the equation we got:

$M-P = e^{-kt} e^{-c}$

And solving for P we got:

$P(t) = M- e^{-kt}e^{-c}$

And replacing $P_o =e^{-c}$ we got:

$P(t) = M - P_o e^{-kt}$

We can use the condition $P(0)=0$ and we got:

$0 = M -P_o e^0$

And we see that $M = P_o$ and replacing we got:

$P= M(1- e^{-kt})$

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3 years ago

Create a factor tree for 21

sveticcg [70]

21 / \
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5 0

4 years ago

Read 2 more answers

WILL MARK branniest answer if gotten right

Jobisdone [24]

Answer:

Line MN is the answer

Step-by-step explanation:

Image SQ as a line that extends forever, if you took line segment and also made it extend forever, then it would become parallel to line segment SQ, never touching or intersecting and going at the same angle.

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3 years ago