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3 years ago

Someone help me with this question please! I'm having a hard time answering it!

Mathematics

1 answer:

Ghella [55]3 years ago

4 0

Step-by-step explanation:

2 * 2 for potatoes = £4

3 * 3 for carrots = £9

90p * 3 for turnips = 270p = £2.70

total price = 9+4+2.70=15.70

change = 20 - 15.70 = £4.30

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Studying a group of children from first grade through high school to see the effect of pre-schooling on educational success woul

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Longitudinal study

Step-by-step explanation:

Information is collected over extended periods of time in a longitudinal study, but in cross-sectional, natural observation, and experimental studies, information is collected over short periods of time or in one time only. Based on the choices given, this type of study would be a longitudinal study.

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2 years ago

an athlete completes a race in 55.72 seconds how many times greater is the digit in the tens place than the digit in the ones pl

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7 is 5 greater than the 2

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3 years ago

Read 2 more answers

Use the FOIL method to evaluate the expression

In-s [12.5K]

So u multiply each term in the first parentheses by each term in the second parentheses.

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2 years ago

Mike owes his friend $6. Each day, Mike earns $3 per day.

raketka [301]

Answer:

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Step-by-step explanation:

8 0

2 years ago

given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

6 0

3 years ago