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4 years ago

Positive numbers are to the number line_______ of the zero on the number line.

Mathematics

1 answer:

yKpoI14uk [10]4 years ago

6 0

Positive number are on the right of the zero on the number line.

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Evaluate. 7^3 <br> A) 21<br> B) 49<br> C) 81<br> D) 343

Mademuasel [1]

The answer is a 73/3=21

5 0

3 years ago

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Bella cycled a total of 12 kilometers by making 4 trips to work. How many trips will Bella have to make to cycle a total of 18 k

UkoKoshka [18]

6 trips because 1 trip = 3 km
If you divide 18 / 3 it would be 6 and by that multiply the # of trips.

6 0

3 years ago

Please help i beg i never get these right

Anuta_ua [19.1K]

Answer:

$\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}$

Step-by-step explanation:

Given

$\sin(105^o)$

Required

Solve

Using sine rule, we have:

$\sin(A + B) = \sin(A)\cos(B) + \sin(B)\cos(A)$

This gives:

$\sin(105^o) = \sin(60 + 45)$

So, we have:

$\sin(60 + 45) = \sin(60)\cos(45) + \sin(45)\cos(60)$

In radical forms, we have:

$\sin(60 + 45) = \frac{\sqrt 3}{2} * \frac{\sqrt 2}{2} + \frac{\sqrt 2}{2} * \frac{1}{2}$

$\sin(60 + 45) = \frac{\sqrt 6}{4} + \frac{\sqrt 2}{4}$

Take LCM

$\sin(60 + 45) = \frac{\sqrt 6 + \sqrt 2}{4}$

Rewrite as:

$\sin(60 + 45) = \frac{\sqrt 2 + \sqrt 6}{4}$

Hence:

$\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}$

3 0

3 years ago

Can you guys help me solve this problem

Maslowich

PLEASE. MARK ME AS BRAINLIEST ANSWER.

8 0

2 years ago

Write the equation 2x + 6x + y2 - 8y= 19 in standard form

wariber [46]

Y^2+8x-8y=19... I think?

3 0

3 years ago

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