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Masja [62]
3 years ago
8

Sorry its blurry but please hurry!!!!!!! Answer 9 and 10 please!!!!

Mathematics
1 answer:
WITCHER [35]3 years ago
6 0

Answer:

9. 31/2 or 15.5( I think that's the answer)

10. B

Step-by-step explanation:

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Find the area of rectangle $BCEF$ . Round the area to the nearest whole number, if necessary.
WINSTONCH [101]

Answer:

999

Step-by-step explanation:

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3 years ago
What is Index Law 2?<br> please give definition
ioda

LAW 2: The second law of indices tells us that when dividing a number with an exponent by the same number with an exponent, we have to subtract the powers. In algebraic form, this rule is as follows . The a represents the number that is divided by itself and m and n represent the powers.

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3 years ago
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Solve the problem. Use the Central Limit Theorem.The annual precipitation amounts in a certain mountain range are normally distr
bazaltina [42]

Answer:

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 109.0 inches, and a standard deviation of 12 inches.

This means that \mu = 109, \sigma = 12

Sample of 25.

This means that n = 25, s = \frac{12}{\sqrt{25}} = 2.4

What is the probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches?

This is the p-value of Z when X = 112. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{112 - 109}{2.4}

Z = 1.25

Z = 1.25 has a p-value of 0.8944.

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

7 0
3 years ago
What is the surface area of this pyramid<br>​
dimulka [17.4K]

Answer:1,152

you have to multiply each side :)

Step-by-step explanation:

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3 years ago
The fractions of -42/-45 and 14/15 are equivalent
FromTheMoon [43]
Yes, that is true, you have to simplify -42/-45 to be able to see if they are equivalant.
\frac{ - 42}{ - 45} = \frac{14}{15}
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3 years ago
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