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Galina-37 [17]
3 years ago
9

Create two different real-world scenarios—one in which you would use permutations and one in which you would use combinations: I

nclude specific details and an explanation about what makes each situation either a combination or permutation.
Provide sample data and calculate the total number of possible permutations and combinations for both scenarios.
Mathematics
1 answer:
LenKa [72]3 years ago
6 0
Permutation: In a race of 10 students, find the number of ways students can finish 1st, 2nd, and 3rd. In this case the order matters, so it is a permutation.
10 x 9 x 8 = 720 ways

Combination: In a class of 10 students, find the number of ways a group of 3 students can be selected to win a prize. In this case the order doesn't matter, so it's a combination.
10 x 9 x 8 / (3 x 2 x 1) = 120 ways
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PLS HELP
prohojiy [21]

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7 0
3 years ago
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4 0
2 years ago
17. Classify Each Angle Pair then find the value of X
IRISSAK [1]

<u>Given</u> -

  • If l || m, m∠1 = (13x + 24)°, and m∠2 = (5x-6)°,

<u>To find</u> -

  • m∠2.

<u>Concept</u> -

Whenever two parallel lines are cut by a transversal, an interesting relationship exists between the two interior angles on the same side of the transversal. These two interior angles are supplementary angles. Hence, according to the figure l and m are two parallel lines and t is the transversal intersecting them then ∠1 + ∠2 = 180°.

<u>Solution</u> -

\rightarrow\sf{(13x+24)^{ \circ}+(5x-6)^{ \circ}=180^{ \circ}}

\rightarrow\sf{13x+5x+24-6=180}

\rightarrow\sf{18x+18=180}

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Henceforth, m∠2 = 39°

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