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navik [9.2K]
3 years ago
14

X/2 + 3 = 4 with work shown

Mathematics
2 answers:
expeople1 [14]3 years ago
4 0
If you think of it, you have to plug in different numbers. Let's try 4. 4 dived by 2= 2+3=5 Uh, oh, too big Ok, let's try a smaller #. What about 2? 2/2=1+3=4 ?=2
7nadin3 [17]3 years ago
3 0
Your answer is x equals 2 
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Edge lengths are given in units. Find the surface area of each prism in square units
castortr0y [4]

Answer:

<u>274 square units</u>

Step-by-step explanation:

<u>Surface Area of the prism</u>

  • SA = 2(base x height) + 2(length x height) + 2(base x length)
  • SA = 2(bh + lh + bl)

<u>Here</u> :

  1. b = 4
  2. h = 5
  3. l = 13

<u>Solving</u>

  • SA = 2(4 x 5 + 13 x 5 + 4 x 13)
  • SA = 2(20 + 65 + 52)
  • SA = 2(137)
  • SA = <u>274 square units</u>
4 0
3 years ago
Read 2 more answers
Please solve. And thank you
Mice21 [21]

Answer:

-12

Step-by-step explanation:

6 0
3 years ago
Ralph is an electrician. He charges an initial fee of $24, plus $33 per hour. If Ralph earned $189 on a job, how long did the jo
11111nata11111 [884]
Charge of Ralph:

Charge = $24  + $33 per hour

Let the time worked be = x.

For x hours, the cost = 33*x = 33x

Charge = 24 + 33x

24 + 33x = 189

33x = 189 - 24

33x = 165

x = 165/33

x = 5

The job took 5 hours.

I hope this helped
3 0
3 years ago
A candy store uses a 50% markup on cost. Find out the owners cost of a candy bar that sells for $1.50.​
bulgar [2K]

Answer:

The owners' cost of the candy bar is $1

Step-by-step explanation:

Assume that the owners' cost of the candy bar is 100%

∵ The owners' cost of the candy bar is 100%

∵ The candy store uses a 50% markup on cost

∵ The selling cost = owners' cost + markup

∴ The selling cost = 100% + 50% = 150%

∵ The candy bar sells for $1.50

→ That means 1.50 is 150% of the owners' cost

∴ 1.50 = 150% × owners' cost

→ Change 150% to decimal by divide it by 100

∵ 150% = 150 ÷ 100 = 1.50

∴ 1.50 = 1.50 × owners' cost

→ Divide both sides by 1.50

∴ 1 = owners' cost

∴ The owners' costs = $1

∴ The owners' cost of the candy bar is $1

5 0
3 years ago
Xander says that it is not possible to draw a quadrilateral that is not a parallelogram and not a trapezoid. Devin says it is po
Olenka [21]
A good place to start for this question is to define the properties of the geometric terms you are given.

Quadrilaterals have four straight sides. 

Parallelograms are quadrilaterals that have two pairs of parallel sides. The opposite sides and opposite angles are congruent. Squares, rectangles, and rhombuses are examples of parallelograms.

Trapezoids are also quadrilaterals. They have only one pair of parallel sides.

So we're looking to see if there are any four-sided shapes that can be made with no parallel sides. The attached picture shows an example of a quadrilateral that is not a parallelogram and is not a trapezoid. Based on these properties of polygons, the correct answer is B. 

6 0
4 years ago
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