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Zina [86]
3 years ago
10

Identify this sequence: 12,19,26,33,40,47. The next term is___??

Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0
Next term is 54. 47+7=54
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HELP QUICK!!
MA_775_DIABLO [31]

Answer:

5

Step-by-step explanation:

The clothing store already sold $300 .

They need to sell x jeans to get to $500.

$500 - $300

$200

They’re $200 short of their goal.

A pair of jeans cost $40

Therefore x40 = $200

x = 200/40

x = 5

So ,they need to sell 5 pairs of jeans to hit their $500 target

5 0
4 years ago
The duration of a light bulb before it burns out follows an exponential distribution averaging 8 months. You are asked: 1) Calcu
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Answer:

The bulb will last less than 800 hours is 0.550

Step-by-step explanation:

6 0
3 years ago
Factor x2 + 29x - 30.
marysya [2.9K]
Ok the w to your question is to cross multiply <span>216=9m m=24

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8 0
3 years ago
Read 2 more answers
How do i find the scale factor?
AnnyKZ [126]

Answer:

1:3.7

Step-by-step explanation:

1331/27

Then cube root

3.66666666667

Round

3.7

(i believe)

8 0
3 years ago
To help consumers assess the risks they are​ taking, the Food and Drug Administration​ (FDA) publishes the amount of nicotine fo
Anni [7]

Answer:

The 90​% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 9 - 1 = 8

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.8595

The margin of error is:

M = T*s = 1.8595*2.7 = 5

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 25.3 - 5 = 20.3 milligrams

The upper end of the interval is the sample mean added to M. So it is 25.3 + 5 = 30.3 milligrams.

The 90​% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.

7 0
3 years ago
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