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guapka [62]
4 years ago
8

Does adding values that are much greater or much less than the other values in a set of data affect the median of the set

Mathematics
1 answer:
butalik [34]4 years ago
4 0
Well, first off, after you've arranged the entire set numerically, the median is the middle number.  Therefore, depending on the numbers in the set, adding another number has the possibility of changing the median. However, it does not matter if the additional values are much greater or much less than the other values.
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The process of manipulating one or more independent variables and measuring their effect on one or more dependent variables whil
frutty [35]

Answer: Ok, let's think our dependent variable like the position of a car with velocity of 50km/h, and our independent variable the time.

so, you can choose any time you want, and for each time, the car will be in a different position, so the position is a variable dependent of the time.

let's suppose you don't know the velocity of the car.

first you see the position at a time t₁ and the position is r₁.

then you see the position at time t₂, and the result is r₂.

here you changed the independent variable and observed how the dependent variable changed. And in this case, with the 4 numbers you observed you can obtain the velocity of the car.

So yes, you can call it an experiment.

3 0
4 years ago
Read 2 more answers
Tall Tex Electronics produced a new game software. Sales of this software amounted to approximately$813,000 last year. Total mar
mash [69]

Answer: 4.7%

Step-by-step explanation:

i took this

4 0
3 years ago
Please help with this problem<br><br> 32n^4<br> _____=<br><br> 4n^2
sertanlavr [38]

Answer:

4*n^2 and n cannot equal 0

Step-by-step explanation:

First, since you have a variable int he denominator you need to write on the side that n cannot = 0, you may write it as n=/= 0, so a slash through an equal sign.  You need to include this with your answer.

I'm assuming this is a fraction.The concept is actually pretty simple.  What happens if you have 2/4?  You can simplify it into 1/2.  The concept is basically saying 2/(2*2) and here 2/2 = 1 so the 2 ont he top cancels out with one of the 2s on the bottom.  This canceling only works for multiplication and division.

You can also do this with variables.  x^3/x^7 can be rewritten as (x*x*x)/(x*x*x*x*x*x*x).  here the three on top cancel out three ont he bottom leaving 1/(x*x*x*x) = 1/x^4.  This also works if there are more on top.  x^8/x^2 = x^6.

We do both in your problem.  Let's work with one at a time.  First the numbers.  32/4 = 8  Now the variables n^4/n^2 = n^2 because two of the ns int he numerator canceled the two in the denominator.  Now put them together to have your answer.  4n^2 and you have to add that n=/=0

4 0
4 years ago
Joan descends down a
Kipish [7]

Answer:

28

Step-by-step explanation:

140 / 5 = 28

4 0
3 years ago
HELP ASAP <br> (will give brainliest)!
Savatey [412]

Answer:

42°

Step-by-step explanation:

∠NML = ∠ZYX =88°

Angles in a triangle add up to 180 so ∠ZXY =

180 - (50+88)

180-138

42

∠ZXY = 42°

3 0
3 years ago
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