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4 years ago

13

when you catch a baseball ,what kind of work do you do ,negative or positive ? by catching the ball , what do you change ? what

energy does it gain or lose ?

1 answer:

Alex Ar [27]4 years ago

4 0

You would use negative energy. You change the balls energy by stopping it and oc course it loses energy becasue it has stoped in your hand.

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A 0.144 kg baseball is moving towards home plate with a speed of 43.0 m/s when it is bunted. the bat exerts an average force of

Ganezh [65]

As per impulse momentum theorem we know that

$F\Delta t = m(v_f - v_i)$

now here we will have

$F = 6.50 \times 10^3 N$

t = 1.30 ms

m = 0.144 kg

$v_i = -43 m/s$

now we need to find final speed using above formula

$(6.50 \times 10^3)(1.30 \times 10^{-3}) = 0.144 ( v_f - (-43))$

$v_f = 15.7 m/s$

so final speed is given as above

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3 years ago

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Answer:

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Which concept rejects existing cultural patterns in society and promotes moving away from them?

yawa3891 [41]

The answer to this item is letter "C. counterculture". Those who are believers in this concept persuade individuals to run counter or move away from the norms that are preset or established in the society. The counterculture may also pertain to certain beliefs, styles, values, and attitudes that is varied from the prevailing culture.

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3 years ago

An apple dropped from the branch of a tree hits the ground in 0.5 s. If the acceleration of the apple during its motion is 10 ms

Ipatiy [6.2K]

Given that,

Time = 0.5 s

Acceleration = 10 m/s²

(I). We need to calculate the speed of apple

Using equation of motion

$v=u+at$

Where, v = speed

u = initial speed

a = acceleration

t = time

Put the value into the formula

$v=0+10\times0.5$

$v=5\ m/s$

(III). We need to calculate the height of the branch of the tree from the ground

Using equation of motion

$s=ut+\dfrac{1}{2}gt^2$

Put the value into the formula

$s=0+\dfrac{1}{2}\times10\times(0.5)^2$

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(II). We need to calculate the average velocity during 0.5 sec

Using formula of average velocity

$v_{avg}=\dfrac{\Delta x}{\Delta t}$

$v_{avg}=\dfrac{x_{f}-x_{i}}{t_{f}-t_{0}}$

Where, $x_{f}$ = final position

$x_{i}$ = initial position

Put the value into the formula

$v_{avg}=\dfrac{1.25+0}{0.5}$

$v_{avg}=2.5\ m/s$

Hence, (I). The speed of apple is 5 m/s.

(II). The average velocity during 0.5 sec is 2.5 m/s

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3 years ago

Vector A is 3 m long and vector B is 4 m long. The length

LUCKY_DIMON [66]

Answer:d

Explanation:

Given

Magnitude of Vector A is 3 m

and Magnitude of vector B is 4 m

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and its minimum value can be 1 m when both are at angle of $180 ^{\circ}$

So the resultant must lie between 1 m to 7 m

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