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bagirrra123 [75]
3 years ago
7

A 0.144 kg baseball is moving towards home plate with a speed of 43.0 m/s when it is bunted. the bat exerts an average force of

6.50 × 103 n on the ball for 1.30 ms. the average force is directed towards the pitcher, which we take to be the positive x direction. what is the final speed of the ball?
Physics
1 answer:
Ganezh [65]3 years ago
6 0

As per impulse momentum theorem we know that

F\Delta t = m(v_f - v_i)

now here we will have

F = 6.50 \times 10^3 N

t = 1.30 ms

m = 0.144 kg

v_i = -43 m/s

now we need to find final speed using above formula

(6.50 \times 10^3)(1.30 \times 10^{-3}) = 0.144 ( v_f - (-43))

v_f = 15.7 m/s

so final speed is given as above

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