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bagirrra123 [75]
3 years ago
7

A 0.144 kg baseball is moving towards home plate with a speed of 43.0 m/s when it is bunted. the bat exerts an average force of

6.50 × 103 n on the ball for 1.30 ms. the average force is directed towards the pitcher, which we take to be the positive x direction. what is the final speed of the ball?
Physics
1 answer:
Ganezh [65]3 years ago
6 0

As per impulse momentum theorem we know that

F\Delta t = m(v_f - v_i)

now here we will have

F = 6.50 \times 10^3 N

t = 1.30 ms

m = 0.144 kg

v_i = -43 m/s

now we need to find final speed using above formula

(6.50 \times 10^3)(1.30 \times 10^{-3}) = 0.144 ( v_f - (-43))

v_f = 15.7 m/s

so final speed is given as above

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Explanation:

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A pendulum of length L=36.1 cm and mass m=168 g is released from rest when the cord makes an angle of 65.4 degrees with the vert
pychu [463]

(a) -0.211 m

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the full length of the pendulum when the mass is at the lowest position is

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(b) 0.347 J

The work done by gravity is equal to the decrease in gravitational potential energy of the mass, which is equal to

\Delta U = mg \Delta y

where we have

m = 168 g = 0.168 kg is the mass of the pendulum

g = 9.8 m/s^2 is the acceleration due to gravity

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So, the work done by gravity is

W=(0.168 kg)(9.8 m/s^2)(0.211 m)=0.347 J

And the sign is positive, since the force of gravity (downward) is in the same direction as the vertical displacement of the mass.

(c) Zero

The work done by a force is:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and the displacement

In this situation, the tension in the string always points in a radial direction (towards the pivot of the pendulum), while the displacement of the mass is tangential (it follows a circular trajectory): this means that the tension and the displacement are always perpendicular to each other, so in the formula

\theta=90^{\circ}, cos \theta = 0

and so the work done is zero.

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