<span>Work=32unit</span><span>...hopes thats helps</span>
a) The velocity of the boat relative to the shore is 3.40 m/s and b) The position of the boat relative to its point of origin after 3s is 10.20m.
Here it is given that the speed of the boat (x) = 2.20m/s
The speed of the stream current (y) = 1.20m/s
a) We have to find the velocity of the boat relative to the shore.
The speed of the boat = x + y
= 2.20 + 1.20
= 3.40m/s
b) Now we have to find the position of the boat after 3s
The formula for speed:
Speed = Distance/ Time
distance = speed × time
speed = 3.40m/s
Time = 3s
distance = 3.40 × 3
= 10.20 m
Therefore we get a) speed as 3.40m/s and b) distance as 10.20m.
To know more about the boat and stream refer to the link given below:
brainly.com/question/382952
#SPJ4
True, they used them because its easier to trade coins than products
Answer:
The answer to your question is : vf = 15.18 m/s
Explanation:
Data
vo = 24 m/s
d = 120 m
vf = ? when d = 60.0 m
Formula
vf² = vo² + 2ad
For d =100m
a = (vf² - vo²) / 2d
a = (0 -24²) / 2(100)
a = -576/200
a = 2.88 m/s²
Now, when d = 60
vf² = (24)² - 2(2.88)(60)
vf² = 576 - 345.6
vf² = 230.4
vf = 15.18 m/s