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Aleonysh [2.5K]
3 years ago
14

If the force on an object is negative, what is known about the change in velocity?

Physics
1 answer:
hoa [83]3 years ago
7 0
A. The velocity will decrease.
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Which material is more closely related to the styrofoam? a. heat exchanger b. diffuser c. insulator d. electrical conductor
nirvana33 [79]

The material that is more closely related to the Styrofoam insulator.

Styrofoam is the term that is used for polystyrene foam in a trademark form. It is a petroleum-based plastic.

Keeping something warm includes the stopping of the transfer of heat from one object to another. This is how insulation works.

Styrofoam is an insulator, which means it'll help keep the heat from the environment out of your cooler. However, you'll still need cooling agents (like ice packs) to make the cooler cold in the first place.

Styrofoam is usually made mostly of air, which means it is a poor conductor of heat, but an excellent convector. It traps the air in small pockets, which blocks the flow of heat energy. This reduces both conduction and convection and makes Styrofoam a good insulator.

To learn more about Styrofoam here

brainly.com/question/21369568

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8 0
2 years ago
Which is equal to a temperature of 20°C? <br>20°F <br>68°F<br>36°F <br>32°F
Dahasolnce [82]
The correct answer would be 68°F because (20°C × 9/5) + 32 = 68°F.
4 0
4 years ago
Read 2 more answers
A slingshot fires a pebble from the top of a building at a speed of 17.5 m/s. The building is 31.5 m tall. Ignoring air resistan
Jlenok [28]

Answer:

The speed with which the pebble strikes the ground is 30.4m/s

Explanation:

Initial velocity (u) = 17.5m/s, height (h) = 31.5m, acceleration due to gravity (g) = 9.8m/s^2

V^2 = u^2 + 2gh = 17.5^2 + 2×9.8×31.5 = 306.25 + 617.4 = 923.65

V^2 = 923.65

V = √923.65 = 30.4m/s

6 0
4 years ago
Ammonia enters the compressor of an industrial refrigeration plant at 2 bar, −10°C with a mass flow rate of 15 kg/min and is com
Juli2301 [7.4K]

Answer:

a) W=85.225 kW

b) 0.02\frac{kW}{K}

Explanation:

First, consider the energy balance for the compressor: The energy that enters to the system (W and enthalpy of the feed flow) is equal to the energy that goes out from it (Heat Q and enthalpy of the exit flow):

W+m*h_1=Q+m*h_2\\W=Q+m*(h_2-h_1)

Consider the enthalpy data from van Wylen 6th edition, Table B.2.2. According to that, h_1=h(200kPa,-10C)=1440.6\frac{kJ}{kgK},  h_2=h(1200kPa,140C)=1757.5\frac{kJ}{kgK}

So, the power input to the compressor is:

W=6kW+15\frac{kg}{min}*\frac{min}{60s}*(1757.5-1440.6)\frac{kJ}{kg}\\W=85.225kW

b) The differential entropy change dS for a reversible heat transfer dQ at a temperature T is:

dS=\frac{dQ}{T}

This equation can be integrated if the heat transfer surface temperature remains constant, which is the case, giving as a result:

S_2-S_1=\frac{Q}{T}=\frac{6kW}{300K}=0.02\frac{kW}{K}

6 0
3 years ago
Imagine that you’re observing a collision. Which action would allow you to determine whether the collision is inelastic?
Thepotemich [5.8K]

The answer is B;) in plato

3 0
3 years ago
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