If the perimeter of equilateral triangle is 77 and the equation showing the perimeter is 6.5X-1 then the value of X is equal to 12.
Given that the perimeter of equilateral triangle is 77 and the expression showing the perimeter is 6.5X-1.
We are required to find the value of X which is used in the expression.
Expression is combination of numbers, fraction, coefficients, indeterminants, determinants, which are mostly not found in equal to form.
Perimeter which is given is 77 and 6.5X-1.
6.5X-1=77
6.5X=77+1
6.5X=78
X=78/6.5
X=12
Hence if the perimeter of equilateral triangle is 77 and the expression showing the perimeter is 6.5X-1 then the value of X is equal to 12.
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Answer:
uhhhh maybe add a picture ?
Step-by-step explanation:
The intersected arc is the arc opposite the angle in question, here arc ABE.
Answer: ABE, last choice
Answer:
It's simple.
So, 30 is half of 15. And 3x5=15 So, I think the best estimate would be 15+15=30 pieces.
Meaning the two pieces are both of the fiveteens.
<u />(x/6) + 42 + (2x/5) - (8x/3) - 19
Change the denominators (numbers below the fraction bar to a to a common number for the three numbers: 6, 5, and 3... in other words to a number that is divisible by all three numbers)
(5x/30) + (12x/30) - (80x/30) + 23
(-63x/30) + 23
<u>
</u><u />And the answer is.....
<u>
(-21x/10) + 23</u>
