Answer:
this is my answer
Step-by-step explanation:
The expression P(−1.33<z<1.59) represents the area under the standard normal curve above a given value oz. Use your standard normal table to find the indicated area. Use a sketch of the standard normal curve with the appropriate area shaded to help find the answer.What is the value of P(−1.33<z<1.59) between the given values oz?Express your answer rounded to 4 decimal places.The scores on a standardized test are normally distributed with a mean of 500 and a standard deviation of 100.Sofia scored 632 on the test.What percent of students scored below Sofia?Round your answer to the nearest hundredth.The scores on a standardized test are normally distributed with a mean of 500 and a standard deviation of 100.Benita scored 432 on the test.What percent of students scored below Benita?Round your answer to the nearest hundredth.The expression P(z<1.00) represents the area under the standard normal curve below a given value oz. Use your standard normal table to find the indicated area. Use a sketch of the standard normal curve with the appropriate area shaded so this is going to let you find the answer.
Step-by-step explanation:
step 1. if k is a zero then (x - 1) is a factor of 4x^3 + 23x^2 - 34x + 7.
step 2. we "can" use long division but synthetic division is easier!
step 3. 1 4 23 -34 7
4. 4. 27. -7.
4 27. -7. 0 (must get 0)
step 4. so the factors are (x - 1)(4x^2 + 27x - 7).
step 5. please note if you multiply these factors together you will get the original polynomial!
elevation in feet = 8.56(140) + 674
elevation in feet = 1872.4
Round to the nearest whole number: 1872
Answer: 1872
Answer:
131 cm
Step-by-step explanation:
formula for surface area of pyramid is
S = (1/3)Bh
but the base ia a square, so B = 
S = (1/3)
the pic shows h = 8
but we don't know x
do SohCahToa
sin60 = x/8
x = 8sin60
x = 6.92820323 or 7
plug in numbers
S = (1/3)
8
S = 392/3
S = 130.6666667 or 131 cm
Answer:
The difference in the areas of the cross-sections is 20 m².
Step-by-step explanation:
^^^
