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3 years ago

PLEASE HELP THANK YOU BRANLIEST IS PROVIDED

Mathematics

2 answers:

Eduardwww [97]3 years ago

8 0

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Hope It helpS

~ʆᵒŕ∂ཇꜱꜹⱽẻⱮë

Nastasia [14]3 years ago

3 0

Answer:

Solution given;

area of semi circle=½πr²=1/2×3.14×4²=25.12in²

area of rectangle ABCD=l×b=8×13=104in²

area of rectangle CEFI=l×b=3×6=18in²

Total area =25.12+104+18=147.12in²

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SOMEONE HELP PLS 15 POINTS FOR ONE EASY MC QUESTION

Ksenya-84 [330]

Answer:

A rectangle could not be a cross section of a cylinder

could you help me with this: brainly.com/question/21423860

6 0

3 years ago

3√x -2/x^2 please show step by step of differentiation before combining the terms.

EastWind [94]

Answer:

Step-by-step explanation:

Before we differentiate, let us assign a variable to the function. Let y be equal to the function i.e let y = 3√x -2/x²

In differentiation if $y = ax^{n}$ , then $\frac{dy}{dx} = nax^{n-1}$ where n is a constant and dy/dx means we are differentiating the function y with respect to x.

Applying the formula o the question given;

$y= 3\sqrt{x} -2/x^2\\y = 3{x}^\frac{1}{2} - 2x^{-2} \\\\$

On differentiating the resulting function;

$\frac{dy}{dx} = \frac{1}{2}*3x^{\frac{1}{2}-1 } - (-2)x^{-2-1} \\\\\frac{dy}{dx} = \frac{1}{2}*3x^{-\frac{1}{2}} + 2x^{-3}\\ \\\frac{dy}{dx} = \frac{1}{2}*{\frac{3}{x^{\frac{1}{2} } }} + \frac{2}{x^{3} } \\\\\frac{dy}{dx} = {\frac{3}{2x^{\frac{1}{2} } }} + \frac{2}{x^{3} }\\\\\frac{dy}{dx} = {\frac{3}{2\sqrt{x} }} + \frac{2}{x^{3} }$

To combine the terms, we will add up by finding their LCM.

$\frac{dy}{dx} = {\frac{3}{2\sqrt{x} }} + \frac{2}{x^{3} }\\\frac{dy}{dx} = \frac{3x^3+4\sqrt{x} }{2x^{3} \sqrt{x}}$

3 0

4 years ago

What’s the exact volume of the figure?

Anna11 [10]

Answer:890.12 cm^3

Step-by-step explanation:

The formula for the volume of a cylinder is

$V=\pi *r^2*h$

V=628.3185307 cm^3

or simply

V=628.32 cm^3

Since, you know the radius of the hemisphere on top, you also know the radius since the height of the hemisphere is the same as it is wide.

Next, the formula for the volume of a sphere is

$V=\frac{4}{3} \pi *r^3$

so the volume of a hemisphere is half of that or:

$V=\frac{2}{3} *\pi *r^3$

V= 261.7993878 cm^3

or simply

V=261.80 cm^3

Finally, you add both of the volumes together to get

V= 890.1179185 cm^3

or simply

V=890.12 cm^3

8 0

3 years ago

A publishing company claims that in fall 2019, the average price of college textbooks for a single semester is $385. Suppose you

hram777 [196]

Answer:

We accept H₀ . We don´t have enough evidence to express the publisher claim is not true

Step by Step explanation:

We must evaluate if the mean of the price of college textbooks is different from the value claimed by the publisher

n < 30 then we must use t - distrbution

degree of freedom n - 1 df = 22 - 1 df = 21

As the question mentions " different " that means, a two-tail test

At 0,01 significance level α = 0,01 α/2 = 0,005

and t(c) = 2,831

Test Hypothesis

Null Hypothesis H₀ μ = μ₀

Alternative hypothesis Hₐ μ ≠ μ₀

To calculate t(s)

t(s) = ( μ - μ₀ ) /σ/√n

t(s) = ( 433,50 - 385 ) / 86,92 / √22

t(s) = 2,6171

Comparing t(c) and t(s)

t(s) < t(c)

Then t(s) is in the acceptance region we accept H₀. We don´t have enough evidence to claim that mean price differs from publisher claim

6 0

3 years ago

Write each of the following expressions in the form of Ax^m y^n, where A is a real number and m and n are integers. (x^2y)÷(2yx^

guapka [62]

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2x° + 2x° + 76° = 180° ( being supplementary angle )

4x° = 180° - 76°

4x° = 104°

x = 104/4

x = 26°

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2 years ago