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3 years ago

PLEASE HELP THANK YOU BRANLIEST IS PROVIDED

Mathematics

2 answers:

Eduardwww [97]3 years ago

8 0

$\huge\fbox\red{⇑ɹ}\huge\fbox\orange{ǝ} \huge\fbox\pink{ʍ}\huge\fbox\green{s}\huge\fbox\blue{u}\huge\fbox\purple{ɐ⇑}\$

➳ $\small\fbox\red{1}\small\fbox\orange{4} \small\fbox\pink{7}\small\fbox\green{.} \small\fbox\blue{1}\small\fbox\purple{2}\small\fbox\pink{Iches²}\$

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Hope It helpS

~ʆᵒŕ∂ཇꜱꜹⱽẻⱮë

Nastasia [14]3 years ago

3 0

Answer:

Solution given;

area of semi circle=½πr²=1/2×3.14×4²=25.12in²

area of rectangle ABCD=l×b=8×13=104in²

area of rectangle CEFI=l×b=3×6=18in²

Total area =25.12+104+18=147.12in²

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The bus fare in a city is $2.00. People who use the bus have the option of purchasing a monthly coupon book for $28.00. With the

LekaFEV [45]

Answer:

56 = 56

Step-by-step explanation:

Given:

Bus fare = $2.00

coupon book = 28.00

bus fare w/ coupon book = $1.00

let x be the number of bus rides.

2.00x = 1.00x + 28.00

2.00x - 1.00x = 28.00

1x = 28.00

x = 28.00

24 bus rides for both to have the same cost.

2.00x = 1.00x + 28

2.00(28) = 1.00(28) + 28

56 = 28 + 28

56 = 56

4 0

3 years ago

Find the curl of ~V ~V = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$