Verify that quadrilateral BCDE is a rhombus with vertices B(–2, 0), C(–7, 5), D(0, 6), and E( 5, 1) by showing that all four sid
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I think you need brackets to clarify what you mean. I think it should be written as
10b/(2b + 8)
If that is the case the reciprocal is
(2b + 8)/10b You just turn everything up side down. There are technical ways of doing this, but the easiest way is just to do what I just did.
Put the numerator in the denominator,
Put the denominator in the numerator.
You could simplify this a bit.
2b/10b + 8/10b
which reduces further.
1/5 + 4/5b
Just to make sure you understand where that b is, I will do this in
Latex.
Alternate answer
If you do mean what your wrote then the reciprocal is 2b / 10b + 8 which is 1/5 + 8 = 8 + 0.2 = 8.2
The 8 has nothing to do with the reciprocal under these conditions.
The answer
I have given you all the choices I can think of without going into decimals. If you have choices, please list them under the comments.
I think you need brackets to clarify what you mean. I think it should be written as
10b/(2b + 8)
If that is the case the reciprocal is
(2b + 8)/10b You just turn everything up side down. There are technical ways of doing this, but the easiest way is just to do what I just did.
Put the numerator in the denominator,
Put the denominator in the numerator.
You could simplify this a bit.
2b/10b + 8/10b
which reduces further.
1/5 + 4/5b
Just to make sure you understand where that b is, I will do this in
Latex.
Alternate answer
If you do mean what your wrote then the reciprocal is 2b / 10b + 8 which is 1/5 + 8 = 8 + 0.2 = 8.2
The 8 has nothing to do with the reciprocal under these conditions.
The answer
I have given you all the choices I can think of without going into decimals. If you have choices, please list them under the comments.