Use the cross product to find the orthogonal vector, solve the parametric equation to see at which (t) the point + orthogonal vector intersects the plane, the distance is (t) * norm of vector
( f + g ) (x) = –2x + 6
( f – g ) (x) = 8x – 2
( f × g ) (x) = –15x2 + 2x + 8
<span>\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}<span><span>(<span><span>g</span><span>f</span><span></span></span>)</span>(x)=<span><span><span>4−5x</span></span><span><span>3x+2</span></span><span></span></span></span></span>
Let's rephrase this:
Here:
There are 3 geometric transformations:
1. Rotation
Shapes are rotated or turned around an axis.
2. Reflection
Shapes are flipped across an imaginary line to make mirror images.
3. Translation
Shapes are slid across the plane.
Answer:
you would need to give the figure
Answer:
Ok y= 2x + b
b referring to any number less than -2 and more than -2
so y=2x+4 can work
Step-by-step explanation:
parallel lines in slope-intercept form have the same slope, i.e. the same 'm' value or coefficient of <em>x</em><em> </em> but different interceptions
