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3 years ago

A bar of soap weighs as much as 3/4 of an identical bar plus 3/4 of a pound. How much does the bar of soap weigh?

1 answer:

5 0

3/4=0.75
Since 3/4 (of the bar) + 1/4 (of the bar) equals a whole bar (1), and 3/4 (of the bar) + 0.75 equals the whole weight of the bar, 0.75 is 1/4 of the bar. 1/4 times 4 equals 1, and 0.75 times 4 equals 3, so the bar of soap weighs 3 pounds.

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Zarrin [17]

First thing you'll need to know is that the value for this equation is actually an approximation 'and' it is imaginary, so, one method is via brute force method.

You let f(y) equals to that equation, then, find the values for f(y) using values from y=-5 to 5, you just substitute the values in you'll get -393,-296,-225,... till when y=3 is f(y)=-9; y=4 is f(y)=48, so there is a change in signs when 'y' went from y=3 to y=4, the answer is between 3 and 4, you can work out a little bit deeper using 3.1, 3.2... You get the point. The value is close to 3.1818...

The other method is using Newton's method, it is similar to this but with a twist because it involves differentiation, so $y_{n+1}=y_n-\frac{f(y)}{f'(y)}$ where 'n' is the number you approximate, like n=0,1,2... etc. f(y) would the equation, and f'(y) is the derivative of f(y), now what you'll need to do is substitute the 'n' values into 'y' to find the approximation.

7 0

3 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago

How to solve a polynomial function

jolli1 [7]

1. A polynomial function is a function that can be written in the form f(x)=anxn +an−1xn−1 +an−2xn−2 +...+a2x2 +a1x+a0, where each a0, a1, etc. represents a real number, and where n is a natural number Here are the steps required for Solving Polynomials by Factoring:

Step 1: Write the equation in the correct form. To be in the correct form, you must remove all parentheses from each side of the equation by distributing, combine all like terms, and finally set the equation equal to zero with the terms written in descending order.
Step 2: Use a factoring strategies to factor the problem.
Step 3: Use the Zero Product Property and set each factor containing a variable equal to zero.
Step 4: Solve each factor that was set equal to zero by getting the x on one side and the answer on the other side.
Example 1 – Solve: 3x3 = 12x

Step 1: Write the equation in the correct form. In this case, we need to set the equation equal to zero with the terms written in descending order.
Step 1
Step 2: Use a factoring strategies to factor the problem.
Step 2
Step 3: Use the Zero Product Property and set each factor containing a variable equal to zero.
Step 3
Step 4: Solve each factor that was set equal to zero by getting the x on one side and the answer on the other side.
Step 4
Example 2 – Solve: x3 + 5x2 = 9x + 45

Step 1: Write the equation in the correct form. In this case, we need to set the equation equal to zero with the terms written in descending order.
Step 1
Step 2: Use a factoring strategies to factor the problem.
Step 2
Step 3: Use the Zero Product Property and set each factor containing a variable equal to zero.
Step 3
Step 4: Solve each factor that was set equal to zero by getting the x on one side and the answer on the other side.
Step 4
Click Here for Practice Problems

Example 3 – Solve: 6x3 – 16x = 4x2

Step 1: Write the equation in the correct form. In this case, we need to set the equation equal to zero with the terms written in descending order.
Step 1
Step 2: Use a factoring strategies to factor the problem.
Step 2
Step 3: Use the Zero Product Property and set each factor containing a variable equal to zero.
Step 3
Step 4: Solve each factor that was set equal to zero by getting the x on one side and the answer on the other side.
Step 4
Click Here for Practice Problems

Example 4 – Solve: 3x2(3x + 4) = 12x(x + 3)

Step 1: Write the equation in the correct form. In this case, we need to remove all parentheses by distributing and set the equation equal to zero with the terms written in descending order.
Step 1
Step 2: Use a factoring strategies to factor the problem.
Step 2
Step 3: Use the Zero Product Property and set each factor containing a variable equal to zero.
Step 3
Step 4: Solve each factor that was set equal to zero by getting the x on one side and the answer on the other side.
Step 4
Click Here for Practice Problems

Example 5 – Solve: 16x4 = 49x2

Step 1: Write the equation in the correct form. In this case, we need to set the equation equal to zero with the terms written in descending order.
Step 1
Step 2: Use a factoring strategies to factor the problem.
Step 2
Step 3: Use the Zero Product Property and set each factor containing a variable equal to zero.
Step 3
Step 4: Solve each factor that was set equal to zero by getting the x on one side and the answer on the other side.
Step 4
Click Here for Practice Problems

7 0

3 years ago

When you’re multiplying or dividing same sign numbers, what will your product or quotient be?

Arturiano [62]

When you multiply two integers with the same signs, the result is always positive. Just multiply the absolute values and make the answer positive. When you multiply two integers with different signs, the result is always negative.

8 0

2 years ago

Read 2 more answers

A girl has $3.35 in her pocket, consisting of dimes and quarters. If there are 23 coins in all, how many of each does she have?

Natalija [7]

Represent
d=number of dimes
q=number of quarters
thererfor
q+d=23

1q=0.25
1d=0.10
therefor

total value=3.35=0.25q+0.1d
so we have
q+d=23
0.25q+0.1d=3.35
solve
q+d=23
subtract q from both sides
d=23-q
subsitute
0.25q+0.1(23-q)=3.35
distribute
0.25q+2.3-0.1q=3.35
group like terms
0.25q-0.1q+2.3=3.35
add like terms
0.15q+2.3=3.35
subtract 2.3 from both sides
0.15q=1.05
multipliy both sides by 100 to get rid of decimal
15q=105
divide both sides by 15
q=7
subsitute
q+d=23
7+d=23
subtract 7
d=16

7 quarters
16 dimes

8 0

2 years ago