What is the Least Common Multiple for (8,17)?
2 answers:
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Answer:
it is a parallelogram
Step-by-step explanation:
so first plot out points and then you find the slope for each of the corresponding lines.
First lets find the slope for AB. you must subtract them and make it -2-1/-2-1. it ends up having a slope of 1.
Then find the slope of the corresponding side(CD). this we will subtract -2-1/3-6. this will have a slope of 1 and will be parallel to AB.
Next you find the slopes of the other two sides starting with AC. we will subtract -2-(-2)/-2-3. this will be a vertical line which means it has a slope of 0.
finally the last step is you see if BD has an equal slope to AC. you then subtract 1-1/1-6. this is also a vertical line so the slope is 0 just like AC so they are both parallel.
in conclusion there are two sets of parallel lines so you have a parallelogram
Answer:
A. (-2.28, 3.38)
Step-by-step explanation:
The confidence interval of the slope :
b ± Tcritical*SE
Tcritical at 95%, df = n - 2 = (15 - 2) = 13
Tcritical = 2.160369
b = slope Coefficient = 0.54924
S.E = 1.311
Hence, we have :
Confidence interval = 0.54924 ± (2.160369 * 1.311)
Confidence interval = 0.54924 ± 2.832243759
Lower boundary = 0.54924 - 2.83224 = - 2.283
Upper boundary = 0.54924 + 2.83224 = 3.3814
The answer option is A. (-2.28, 3.38)
