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d1i1m1o1n [39]
4 years ago
14

POINTS!!! PLS COME AND LOOK!!! I NEED YOU GENIUSES!!! I WILL GIVE BRAINLIEST!!!!! AT LEAST COME AND LOOK!!!! WILL FOREVER BE GRE

AT FULL!!! EASY I JUST STRUGGLE!! 2 QUESTIONS!!
13. Which line is perpendicular to y= -3/4 x+2 if the line passes through the point (3, 5)?

A) y= 4/3 x+1
B) Y-3= 4/3(x-5)
C) y= 4/3x-9
D) y-3= -3/4(x-5)

18. What is the range of y=x+3^2?
A) {3^2}
B) {1, 3, 9}
C) All real numbers except 9.
D) All real numbers
Mathematics
1 answer:
Papessa [141]4 years ago
7 0

Answer:

13.A) y= 4/3 x+1

D) all real numbers

Step-by-step explanation:

y= -\frac{3}{4}  x+2\\(3,5)=(x,y)\\m_1 =-\frac{3}{4} \\\\m_2 = \frac{-1}{-\frac{3}{4} } \\m_2 =4/3\\Substitute\:values\:into\:y=mx+b\:form\\\\5 = \frac{4}{3} (3) +b\\5 = 4+b\\5-4=b\\1=b\\m =4/3\\\\Substitute \:new\:values\:into\:y=mx+b\:form\\\\y = \frac{4}{3} x +1

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If a coordinate is on the x or y axis then it is NOT in a quadrant. True or False?​
Reil [10]
The answer: it is not in a quadrant, true
5 0
3 years ago
Read 2 more answers
The sum of two numbers is −53 and the difference between the numbers is −5.
Ahat [919]

Answer:

-29 and -24

Step-by-step explanation:

-24 = (-29) = -53

-29-(-24) = -5

5 0
3 years ago
Guys help me with the number 1 please
Damm [24]
4y-y is NOT equivalent to 4.
4 is multiplied by 'y', and then 'y' is subtracted from that equation. Even if y=1, your equation would look like 4x1-1=3.


Hope that made sense:)
8 0
3 years ago
Please help. solve for x
malfutka [58]

Step-by-step explanation:

Given,

Base of the triangle

2 \sqrt{6}

Hypotenuse of the triangle = 5

Height of the triangle = x

Therefore, According to Pythagoras Theorem,

{base}^{2}  +  {height}^{2}  =  {hypotenuse}^{2}

=  >  {(2 \sqrt{6)} }^{2}  +  {x}^{2}  =  {5}^{2}

=  > 24 +  {x}^{2}  = 25

=  >  {x}^{2}  = 25 - 24

=  >  {x}^{2}  = 1

=  > x =  \sqrt{1}

=  > x = 1

Hence, the required value of <u>x is 1.</u>

7 0
3 years ago
In a certain school district, it was observed that 32% of the students in the element schools were classified as only children (
kipiarov [429]

Answer:

We conclude that the proportion of only children in the special program is significantly different from the proportion for the school district.

Step-by-step explanation:

We are given that in a certain school district, it was observed that 32% of the students in the element schools were classified as only children (no siblings).

However, in the special program for talented and gifted children, 135 out of 347 students are only children.

<u><em>Let p = population proportion of only children in the special program.</em></u>

So, Null Hypothesis, H_0 : p = 32%     {means that the proportion of only children in the special program is equal to the proportion for the school district}

Alternate Hypothesis, H_A : p \neq 32%     {means that the proportion of only children in the special program is significantly different from the proportion for the school district}

The test statistics that would be used here <u>One-sample z proportion statistics</u>;

                         T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p  = sample proportion of only children in the special program = \frac{135}{347} = 0.39

            n = sample of students = 347

So, <em><u>test statistics</u></em>  =  \frac{0.39-0.32}{\sqrt{\frac{0.39(1-0.39)}{347} } }  

                              =  2.673

The value of z test statistics is 2.673.

<em>Now, at 0.02 significance level the z table gives critical value of -2.3263 and 2.3263 for two-tailed test. Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will in the rejection region due to which </em><u><em>we reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the proportion of only children in the special program is significantly different from the proportion for the school district.

4 0
3 years ago
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