A computer training institute has 625 students that are paying a course fee of $400. Their research shows that for every $20 red
uction in the fee, they will attract another 50 students. What fee should the school charge to maximize their revenue?
1 answer:
Given:
Number of students in the computer training institute = 625 students
Course fee per student = $400
Rate = 50 addt'l students per $20 reduction
Total sales = (625+50x) * ($400-20x)
if reduced by $20, sales = 256500
$40, sales = 261000
$60, sales = 263500
$80, sales = 264000
$100, sales = 262500
The maximum reduction to maximize sales is $80 or $320 per student and 825 students.
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Well, this question is essentially asking what number between 60 and 70 is a multiple of 7.
If you do your multiplication correctly, the number should be 63, which is 7 times 9.
x = 10
The way to solve this one - step equation is to divide by 50 on both sides to get x by itself :
50x=500
x = 10
3x^3 - 7x^2 + 12 - 3x^3 -6x^2 - 10x
= -13x^2 - 10x + 12
Answer is B
-13x^2 - 10x + 12
I'm pretty sure correct me if I'm wrong but is it 27.6 dollars?
Answer:
D is the answer... But I am not 100% sure though sorry.
Step-by-step explanation: