Question

Please help. solve for x

Answer 1

Step-by-step explanation:

Given,

Base of the triangle

$2 \sqrt{6}$

Hypotenuse of the triangle = 5

Height of the triangle = x

Therefore, According to Pythagoras Theorem,

${base}^{2} + {height}^{2} = {hypotenuse}^{2}$

$= > {(2 \sqrt{6)} }^{2} + {x}^{2} = {5}^{2}$

$= > 24 + {x}^{2} = 25$

$= > {x}^{2} = 25 - 24$

$= > {x}^{2} = 1$

$= > x = \sqrt{1}$

$= > x = 1$

Hence, the required value of x is 1.