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3 years ago

Given the explitic formula, determine which term produces the given answer. f(n)=65-10n; -35

Mathematics

1 answer:

ella [17]3 years ago

8 0

Answer:

The 10th term.

Step-by-step explanation:

n is the term number so we have:-

65 - 10n = -35

-10n = -35 - 65 = -100

n = -100/-10

= 10

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High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers

Maurinko [17]

Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

Step:-1

Given that the mean of the Population = 540HP

Given that the size of the sample 'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

Step(ii):-

Degrees of freedom = n-1 =9-1 =8

t₀.₀₀₅ = 3.3554

The 99% of a confidence interval for the average maximum HP for the experimental engine.

$(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2} + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )$

$(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )$

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

Final answer :-

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

4 0

3 years ago

If you solve this for me I’ll love you forever (but seriously I need the answer ASAP)

mash [69]

Description:

This will be no solution because when we add 10 to both sides of the equation then simplify it. After that we will subtract 6 from both sides. It will give us no solution. For more info please see the attachment.

Answer: No solution

Hope this helps.

8 0

3 years ago

Read 2 more answers

Express each number as a product of its prime factor of 39

vitfil [10]

If you just mean the product of the prime factors of 39 then this is the answer

39 = 3 x 13

5 0

3 years ago

Which statement is true about the extreme value of the given quadratic equation?

ICE Princess25 [194]

Answer:

Option B. The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

The correct quadratic equation is

$y=-3x^{2}+12x-33$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

Convert to vertex form

Factor -3

$y=-3(x^{2}-4x)-33$

Complete the square

$y=-3(x^{2}-4x+2^2)-33+12$

$y=-3(x^{2}-4x+4)-21$

Rewrite as perfect squares

$y=-3(x-2)^{2}-21$

The vertex is the point (2,-21)

therefore

The equation has a maximum value with a y-coordinate of -21

3 0

3 years ago

I really need this it's a test

faltersainse [42]

Move all terms not containing x to the right side of the equation

x=9

8 0

3 years ago