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3 years ago

I need help with this

Mathematics

2 answers:

Debora [2.8K]3 years ago

7 0

The correct answer is A.

If you would like me to explain into further detail, feel free to message me :)

Tamiku [17]3 years ago

6 0

The dog stopped but began running towards the trainer since the distance stopped and went down back and stayed at that distance

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Which point is a solution to the system of inequalities graphed here? y ≤ 2x 2 y ≥ -5x 4

Mandarinka [93]

The point that is a solution to the system of inequalities is (5, 0)

<h3>How to determine the points on the solution?</h3>

The system of inequalities is given as:

y ≤ 2x + 2

y ≥ -5x + 4

Next, we test the given options.

From the list of options, we have

(x, y) = (5, 0)

Substitute (x, y) = (5, 0) in y ≤ 2x + 2 and y ≥ -5x + 4

y ≤ 2x + 2

0 ≤ 2 * 5 + 2

0 ≤ 12 -- this is true

y ≥ -5x + 4

0 ≥ -5 * 5 + 4

0 ≥ -21 -- this is true

Since both results are true, then it means that the point that is a solution to the system of inequalities is (5, 0)

Read more about system of inequalities at:

brainly.com/question/24372553

#SPJ1

Complete question

Which point is a solution to the system of inequalities graphed here? y ≤ 2x + 2

y ≥ -5x + 4

A. (1,6)

B. (-6,0)

C. (0,5)

D. (5,0)

7 0

2 years ago

Ebony is cutting dough for pastries in her bakery. She needs all the pieces to be congruent triangles and has ensured that line

scoray [572]

Answer:

B) Line EG and OM

Step-by-step explanation:

We already know that EF and ON are congruent as well as angle MON and GEF so that means that the only thing we need to know to make it SAS would be EG and OM because we already have the angle and with that length then we know that line FG will be congruent to NM. We would not want to compare NM and FG because then we would get AS* not SAS.

4 0

3 years ago

Read 2 more answers

A taxi service charges an initial $5 fee, plus $2 per mile driven. A. Write an equation to represent the situation. B. How much

yaroslaw [1]

A. 5+2m
B. $305.
This is because 150*2=300, plus an initial fee of five dollars. 300+5 is 305.

8 0

3 years ago

Read 2 more answers

How do i solve 6x-2y=2 and 2+6x=y

qaws [65]

In this case there would be no solution bc the x's are the same

7 0

3 years ago

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The thickness of metal wires used in the manufacture of silicon wafers is assumed to be normallydistributed with meanμ. To monit

yanalaym [24]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ = 10

(b) Alternate Hypothesis, $H_A$ : $\mu\neq$ 10

(c) One-sample t test statistics distribution : T.S. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

(d) The value of the test statistic is 1.054.

(e) The p-value = 0.1493

(f) We conclude that the mean equals the target value of 10 which means that the output can be considered acceptable as it doesn't differs from the target value of 10.

Step-by-step explanation:

We are given that the thickness of metal wires used in the manufacture of silicon wafers is assumed to be normally distributed with mean μ. To monitor the production process, the thickness of 40 wires is taken.

The output is considered unacceptable if the mean differs from the target value of 10. The 40 measurements yield a sample mean of 10.2 and sample standard deviation of 1.2.

Let $\mu$ = mean thickness of metal wires used in the manufacture of silicon wafers.

(a) Null Hypothesis, $H_0$ : $\mu$ = 10 {means that the mean equals the target value of 10}

(b) Alternate Hypothesis, $H_A$ : $\mu\neq$ 10 {means that the mean differs from the target value of 10}

(c) The test statistics that will be used here is One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\mu$ = sample mean = 10.2

s = sample standard deviation = 1.2

n = sample of yields = 40

(d) So, test statistics = $\frac{10.2-10}{\frac{1.2}{\sqrt{40} } }$ ~ $t_3_9$

= 1.054

The value of the test statistic is 1.054.

(e) Now, P-value of the test statistics is given by;

P-value = P( $t_3_9$ > 1.054) = 0.1493

Now at 0.05 significance level, the t table gives critical values between -2.0225 and 2.0225 at 39 degree of freedom for two-tailed test. Since our test statistics lies within the critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

(e) Therefore, we conclude that the mean equals the target value of 10 which means that the output can be considered acceptable as it doesn't differs from the target value of 10.

7 0

3 years ago