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tia_tia [17]
4 years ago
6

Help with this math question please

Mathematics
1 answer:
goldenfox [79]4 years ago
4 0
Amount of money invested: P=$4,100
Interest rate percentage in decimal form: r=7.25%=7.25/100→r=0.0725
Time in years: t=8
Total money in the account at time t: A=?

A=Pe^(rt)
A=$4,100e^(0.0725*8)
A=$4,100e^0.58
A=$4,100(1.786038431)
A=$7,322.757566
A=$7,322.76

Answer: The balance in the account after 8 years is $7,322.76
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in this particular arithmetic sequence, a6 = 36 and a17 = 113. what is the value of a23 a23=101 a23=155 a23=162 a23=167
il63 [147K]
Determine first the common difference (d) of the arithmetic sequence using the given terms,
                             d = (a17 - a6) / (17 - 6) 
                               d = (113 - 36) / 11 = 7
Using the 17th term, 113, we get the value of a23 by,
                             a23 = a17 + (23 - 17) x 7
                                    a23 = 113 + 42 = 155
Thus, the 23rd term is 155. 
5 0
3 years ago
A lumber company had 4 bundles of wood (12 pieces total). What is the rate of pieces per<br> bundle?
slamgirl [31]

Answer:

There are three pieces per bundle.

5 0
3 years ago
EMERGENCY!!! (WILL GIVE BRAINLIEST)
algol [13]
He walked 5 miles.

5x+60y=35
x+y=1.5

Solutions (via elimination or substitution) are:
x=1
y=.5

x is the number of hours he spent walking, and 5x is the number of miles he walked. 5x=5(1)=5 . He walked for 5 miles. 

y is the number of hours he spent on the bus, and 60y is the number of miles he rode on the bus.  60y=60(.5)=30 . He rode the bus for 30 miles. 
7 0
3 years ago
A warehouse distributor of carpet keeps 6,000 yards of deluxe shag carpet in stock during a month. The average demand for carpet
Bond [772]

Answer:

The probability that a customer’s order will not be met during a month is 1.67.

Step-by-step explanation:

Given : A warehouse distributor of carpet keeps 6,000 yards of deluxe shag carpet in stock during a month. The average demand for carpet from the stores that purchase from the distributor is 4,500 yards per month, with a standard deviation of 900 yards.

To find : What is the probability that a customer’s order will not be met during a month?

Solution :

Average Mean \mu=4500

Sample Mean x=6000

Standard deviation \sigma=900

The formula is given by,

Z=\frac{x-\mu}{\sigma}

Substitute the value in the formula,

Z=\frac{6000-4500}{900}

Z=\frac{1500}{900}

Z=1.67

The probability that a customer’s order will not be met during a month is 1.67.

7 0
3 years ago
Solve 3(2+4)÷(10-1) solve this problem math 5th grade
rosijanka [135]

Answer:

<h2>3(2+4)÷(10-1) = 2</h2><h2 />

Step-by-step explanation:

3×(2+4)÷(10-1) = 3×(6)÷(9) = 18÷9 = 2

8 0
3 years ago
Read 2 more answers
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