Answer:
The probability that a customer’s order will not be met during a month is 1.67.
Step-by-step explanation:
Given : A warehouse distributor of carpet keeps 6,000 yards of deluxe shag carpet in stock during a month. The average demand for carpet from the stores that purchase from the distributor is 4,500 yards per month, with a standard deviation of 900 yards.
To find : What is the probability that a customer’s order will not be met during a month?
Solution :
Average Mean 
Sample Mean 
Standard deviation 
The formula is given by,

Substitute the value in the formula,



The probability that a customer’s order will not be met during a month is 1.67.