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tangare [24]
3 years ago
11

Rank from smallest to largest a) 5583 nm b) 0.001 um c) 100 cm d)3.456 x 10^-9

Chemistry
1 answer:
kari74 [83]3 years ago
4 0

Answer:

if it's helpful for you please mark me brainliest answer thanks

Explanation:

5583= 3.456= 100= 0.001

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When two aqueous solutions are mixed together the temperature of the solution decreases?
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Identify the examples of diffusion in the list below. Check all that apply.
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4 0
3 years ago
NH₄NO₃ → N₂O + 2H₂O When 45.70 g of NH₄NO₃ decomposes, what mass of each product is formed?
Anna007 [38]

Answer: 25.13 g of N_2O  and 20.56 g of H_2O will be produced from 45.70 g of NH_4NO_3

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} NH_4NO_3=\frac{45.70g}{80.04g/mol}=0.571moles

The balanced chemical equation is:

NH_4NO_3\rightarrow N_2O+2H_2O  

According to stoichiometry :

1 mole of NH_4NO_3 produce = 1 mole of N_2O

Thus 0.571 moles of NH_4NO_3 will require=\frac{1}{1}\times 0.571=0.571moles  of N_2O  

Mass of N_2O=moles\times {\text {Molar mass}}=0.571moles\times 44.01g/mol=25.13g

1 mole of NH_4NO_3 produce = 2 moles of H_2O

Thus 0.571 moles of NH_4NO_3 will require=\frac{2}{1}\times 0.571=1.142moles  of H_2O  

Mass of H_2O=moles\times {\text {Molar mass}}=1.142moles\times 18g/mol=20.56g

Thus 25.13 g of N_2O  and 20.56 g of H_2O will be produced from 45.70 g of NH_4NO_3

5 0
3 years ago
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