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Elanso [62]
3 years ago
8

The greatest amount of transpiration and evaporation will occur most likely when the air temperature is

Chemistry
2 answers:
jeka57 [31]3 years ago
8 0

high and humidity is low


Alika [10]3 years ago
7 0

Answer:

High Temperature

Explanation:

Transpiration is the process in which water is lost from the plant through evaporation from its leaves. During transpiration, water moves through the plant and is lost through the stomata of the plant as vapour.

Actually, the water absorbed from the soil through the roots of the plant is not fully utilized and the excess is lost through transpiration.This lost through transpiration is more feasible at high temperature because water evaporates faster at higher temperature. At higher temperatures also, the stomata of the leaves of the plants also open up making it easier for transpiration to occur.

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How many grams of O2 are required for the complete reaction of 45.0g of CH4 to form CO2 and H2O?
Wewaii [24]

Answer: 90 g O2

Explanation: soution attached:

Balance first the chemical equation

CH4 + O2 => CO2 +2H2O

Convert mass of CH4 to moles

Use the mole ratio of CH4 and O2 from the balanced equation.

Convert moles of O2 to mass using the molar mass of O2.

6 0
3 years ago
In which reaction does the oxidation number of hydrogen change? In which reaction does the oxidation number of hydrogen change?
dedylja [7]

<u>Answer:</u> The correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

<u>Explanation:</u>

Oxidation number is defined as the number which is given to an atom when it looses or gains electron. When an atom looses electron, it attains a positive oxidation state. When an atom gains electron, it attains a negative oxidation state.

Oxidation state of the atoms in their elemental state is considered as 0. Hydrogen is present as gaseous state.

For the given chemical reactions:

  • <u>Reaction 1:</u>  2HClO_4(aq.)+CaCO_3(s)\rightarrow Ca(ClO_4)_2(aq.)+H_2O(l)+CO_2 (g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 2:</u>  CaO(s)+H_2O(l)\rightarrow Ca(OH)_2(s)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 3:</u>  HCl(aq.)+NaOH(aq.)\rightarrow NaCl(aq.)+H_2O(l)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 4:</u>  2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: 0

Thus, the oxidation state of hydrogen is changing.

  • <u>Reaction 5:</u>  SO_2(g)+H_2O(l)\rightarrow H_2SO_3(aq.)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

Hence, the correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

6 0
3 years ago
HELP!!!!!!! How many moles of AgNO3 must react to form 0.854 mol Ag?<br> mol AgNO3
iris [78.8K]
There is 0.854 moles in AgNO3
4 0
4 years ago
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What is the mole fraction of ethanol in a solution of 3.00 moles of ethanol and 5.00 moles of water?
Rus_ich [418]
If theres a mixture of components we can calculate the mole fraction
mole fraction can be calculated as follows
mole fraction of component = \frac{number of moles of component}{total number of moles of all components }
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mole fraction of ethanol = \frac{3.00 mol}{8.00 mol }
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6 0
4 years ago
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liraira [26]

<span>Animal cell organelles like lysozyme and the mitochondria have roles similar to the organs of the human digestive system.
The </span>lysozyme is like our stomach because digests the food of the cell and has a acidic environment just like a stomach.
The mitochondria is like the intestine because it's responsible for converting the nutrients into energy that the body can use to function.

<span />
6 0
3 years ago
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