Answer: 3.61 L
Explanation:
To calculate the moles, we use the equation:
2 moles of produce = 3 moles of
0.1 moles of produce = moles of
According to the ideal gas equation:'
P = Pressure of the gas = 1 atm (NTP)
V= Volume of the gas = ?
T= Temperature of the gas = 20°C = (20+273) K = 293 K (NTP)
R= Value of gas constant in in kilopascals = 0.0821 Latm/K mol
Thus volume of oxygen at NTP obtained by decomposing 12.26 g of is 3.61 L
Ocean currents act much like a conveyer belt, transporting warm water and precipitation from the equator toward the poles and cold water from the poles back to the tropics. Thus, currents regulate global climate, helping to counteract the uneven distribution of solar radiation reaching Earth's surface.
Answer:
2.29 moles of SF₆ contain 334.5 g SF₆
Explanation:
Given data:
Mass of SF₆ = ?
Number of moles of SF₆ = 2.29 mol
Solution:
Formula:
Mass = number of moles × molar mass
Molar mass of SF₆ = 32.065 + (19)×6
Molar mass of SF₆ = 146.06 g/mol
Now we will put the values in formula.
Mass = 2.29 mol × 146.06 g/mol
Mass = 334.5 g
2.29 moles of SF₆ contain 334.5 g SF₆ .
0.216 moles of gas can the container hold if a sealed container can hold 0.325 L of gas at 1.00 atm and 293 K.
<h3>What is an ideal gas equation?</h3>
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
V=5 L
P = 1.05 atm
T = 296 K
Putting value in the given equation:
Moles = 0.216 moles
Hence, 0.216 moles of gas can the container hold if a sealed container can hold 0.325 L of gas at 1.00 atm and 293 K.
Learn more about the ideal gas here:
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