When the substance is creating gases. Sometimes when it’s bubbling up
In this redox reaction, we must identify which is reduced and which is oxidized. Cl is oxidized from -1 to 0, Mn is reduced from +7 to +2.
<span>MnO−4+Cl−→Mn2++Cl2</span>Balance the number of Cl first.
<span>MnO−4+2Cl−→Mn2++C<span>l2
</span></span><span>MnO−4+10Cl−→2M<span>n2+</span>+5C<span>l2
</span></span>Balance the number of oxygen by adding <span>H2O</span>
<span>2MnO−4+10Cl−→2M<span>n2+</span>+5Cl2+8H2O
</span>Balance the number of H by adding H+
<span>2MnO−4+10Cl−+16H+→2M<span>n2+</span>+5Cl2+8H2O
</span>
Now, we know that there are 2 H+ in <span>H2SO4</span>, so, we can get
<span>2MnO−4+10Cl−+8H2SO4→2M<span>n2+</span>+5Cl2+8H2O
</span>
Put <span>S<span>O2−4</span></span> with <span>M<span>n2+</span></span>
<span>2MnO−4+10Cl−+8H2SO4→2MnSO4+5Cl2+8H2O
</span>
Add K in front of <span>MnO−4</span> and <span>Cl−</span> and balance it on the right
<span>2KMnO4+10KCl+8H2SO4→12K++2MnSO4+5C<span>l<span>2 + 8H20
The final answer is </span></span></span>2KMn<span>O4</span><span>+10KCl+8</span><span>H2</span><span>S</span><span>O4</span><span>→6</span><span>K2</span><span>S</span><span>O4</span><span>+2MnS</span><span>O4</span><span>+5C</span><span>l2</span><span>+8</span><span>H2</span><span>O</span>
Hydrochloric acid is very corrosive. Handling it should be properly taken cared off. Personal protective equipment should be worn at all times when using this substance. PPE includes gloves specific for the substance used, goggles, closed flat shoes and laboratory gown. The same should be done for handling silver nitrate.<span />
The answer is Velocity and potential energy. Kinetic energy is the total energy of a system or an object in motion and requires movement.