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3 years ago

Identify the solution set for: −2|−2x−4|=−12

Mathematics

2 answers:

myrzilka [38]3 years ago

4 0

Answer:

C: {−5, 1)

Step-by-step explanation:

Starting with −2|−2x−4|=−12, divide both sides by -2:

|−2x−4| = 6

Reduce this by dividing all terms by 2:

|-x - 2| = 3

This is equivalent to x + 2 = 3 and x + 2 = - 3

Solving thse two equations, we get x = 1 and x = -5

And so the solution set is C: {−5, 1)

Annette [7]3 years ago

4 0

Answer:

abc i need to put a real answer

Step-by-step explanation:

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Ira Lisetskai [31]

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3 years ago

Please solve for me. please be right

lesantik [10]

Answer:

Step-by-step explanation:

5+3÷5-3=8÷2=4

5 0

2 years ago

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Subtract what she has now from the total she needs. She needs ten. She has one 2 1/3 and 3 1/3 added is 5 2/3

tatiyna

Answer:

4 ⅓

Step-by-step explanation:

10 - 5 ⅔

10 - 5 × 3 + 2/3

10 - 17/3

3 × 10 - 17/3

30 - 17/3

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-TheUnknownScientist

6 0

2 years ago

If lim x-> infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b

MAXImum [283]

We have

$\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}$

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0$

The rational term vanishes as x gets arbitrarily large, so we can ignore that term, leaving us with

$\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0$

and this happens if a = 1 and b = -1.

To confirm, we have

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-x+1\right)=\lim_{x\to\infty}\frac{x^2-(x-1)(x+1)}{x+1}=\lim_{x\to\infty}\frac1{x+1}=0$

as required.

3 0

3 years ago

a sporting goods store has 39 bicycles. if 2/3 of this quantity are sold how many bicycles were sold? please show work

horrorfan [7]

Answer:

Step-by-step explanation:

GIRL 2/3's

2/3*39

2/3*39/1= 78/3 ( DIVIDE ) =26

2/3's of 39 =26

7 0

3 years ago

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