If this question is about percent whole and part then the answer is
PLEASE ANSWER I NEED DONE
2 answers:
The picture in the attached figure
we know that
area of a sector=(∅/2)*r²--------> when ∅<span> is in radians
</span>
area of sector inner circle=(∅/2)*r²
area of sector outer circle=(∅/2)*R²-(∅/2)*r²
<span>The ratio of the area of the sector removed from the outer circle to the area of the sector removed from the inner circle is
</span>[(∅/2)*R²-(∅/2)*r²]/[(∅/2)*r²]-----> [R²-r²]/[r²]
therefore
the answer is
<span>(R^2 - r^2)/r^2</span>
we know that
area of a sector=(∅/2)*r²--------> when ∅<span> is in radians
</span>
area of sector inner circle=(∅/2)*r²
area of sector outer circle=(∅/2)*R²-(∅/2)*r²
<span>The ratio of the area of the sector removed from the outer circle to the area of the sector removed from the inner circle is
</span>[(∅/2)*R²-(∅/2)*r²]/[(∅/2)*r²]-----> [R²-r²]/[r²]
therefore
the answer is
<span>(R^2 - r^2)/r^2</span>
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Assume M is the Total Money
M/6 + (1/5)(M - M/6) + $600 = M
M/6 + M/5 - M/30 + $ 600 = M
M/6 + M/5 - M/30 - M = -$600
(1/6 + 1/5 - 1/30 - 1)M = -$600
-2M/3 = -$600
2M/3 = $600
M = ($600)(3/2)
M = $900
so the total money is $900
but the money he gave to his children is only 1/3 of the Total Money(M)
therefore,
=(1/3)($900)
=$300
$300 is the total money he gave to his children
Assume M is the Total Money
M/6 + (1/5)(M - M/6) + $600 = M
M/6 + M/5 - M/30 + $ 600 = M
M/6 + M/5 - M/30 - M = -$600
(1/6 + 1/5 - 1/30 - 1)M = -$600
-2M/3 = -$600
2M/3 = $600
M = ($600)(3/2)
M = $900
so the total money is $900
but the money he gave to his children is only 1/3 of the Total Money(M)
therefore,
=(1/3)($900)
=$300
$300 is the total money he gave to his children