PLEASE ANSWER I NEED DONE

Mathematics

2 answers:

dezoksy [38]3 years ago

5 0

Answer:

The other answer is wrong. It is r^2/R^2.

Step-by-step explanation:

Troyanec [42]3 years ago

3 0

The picture in the attached figure

we know that
area of a sector=(∅/2)*r²--------> when ∅ is in radians

area of sector inner circle=(∅/2)*r²

area of sector outer circle=(∅/2)*R²-(∅/2)*r²

The ratio of the area of the sector removed from the outer circle to the area of the sector removed from the inner circle is
[(∅/2)*R²-(∅/2)*r²]/[(∅/2)*r²]-----> [R²-r²]/[r²]

therefore

the answer is
(R^2 - r^2)/r^2

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Anybody know the right answer?

Dmitry_Shevchenko [17]

If we just have

$y = \cos x$

that's an amplitude of 1 and a period of $2\pi$

Let's modify this step by step.

Amplitude of 4. Four times the amplitude means a factor of 4 on the outside.

$y = 4 \cos x$

Period of π. Double the period means a factor of 2 on the inside.

$y = 4 \cos(2x)$

Horizontal shift of π/2 to the left. To the left means adding a positive number to x. The question appear ambiguous. It's not clear to me if we add to x or 2x; let's make it

$y = 4 \cos(2(x + \frac \pi 2))$