Let's say you want to compute the probability

where

converges in distribution to

, and

follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing

such that its mean and variance are the same as those for

.
Example: If

is binomially distributed with

and

, then

has mean

and variance

. So you can approximate a probability in terms of

with a probability in terms of

:

where

follows the standard normal distribution.
Answer:
To find out the first three terms of 3n - 2 substitute 1 ,2 and 3 into the equation.
so the three terms a
3(1)-2=1
3(2)-2=6-2=4
3(3)-2=9-2=7
As you can see the sequence goes up in 1,4 and 7.To find out the 10th term you also substitute 10 into the equation so 3(9)-2=18-2=16
so 16 is the tenth term
Hope this helped!
Step-by-step explanation:



→ 11x(7) = 14(9)
→ 77x = 126
→ x = 126 ÷ 77
→ x = 1.63
Hello there!
Carol would have sold 60 subscriptions and Jenifer would have sold 30
The correct answer is option D, 60
I hope this help!