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3 years ago

written as a simplified polynomial in standard form what is the result when (x-5)^2 is subtracted from 7x^2+6x+5

Mathematics

1 answer:

blagie [28]3 years ago

6 0

(7x^2 + 6x + 5 ) - (x - 5)^2
(7x^2 + 6x + 5 ) - (x^2 - 10x + 25)
6x^2 + 16x - 20 is the answer

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Radical 16 * redical 12

alukav5142 [94]

$\sqrt{16}\times\sqrt{12}$

$=\sqrt{4^2}\times\sqrt{2^2\cdot3}$

$=4\times2\sqrt3=8\sqrt3$

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3 years ago

Pls do some research but can I bring a bearded dragon on a 12 hour car trip without any heath issues happening?

creativ13 [48]

Answer:

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3 years ago

Find the percent of the number. explain your method 120%of 75

cupoosta [38]

I would use is over of equals percent over 100 is woudl be 120% and of would be 75 then you would put x over 75

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3 years ago

Read 2 more answers

Consider the implicit differential equation <img src="https://tex.z-dn.net/?f=%2849%20y%5E%7B3%7D%20%2B%2045%20xy%29%20dx%20%2B%

BaLLatris [955]

We're looking for an integrating factor $\mu(x,y)=x^py^q$ such that

$\mu\underbrace{(49y^3+45xy)}_M\,\mathrm dx+\mu\underbrace{(98xy^2+50x^2)}_N\,\mathrm dy=0$

is exact, which would require that

$(\mu M)_y=(\mu N)_x$
$(49x^py^{q+3}+45x^{p+1}y^{q+1})_y=(98x^{p+1}y^{q+2}+50x^{p+2}y^q)_x$
$49(q+3)x^py^{q+2}+45(q+1)x^{p+1}y^q=98(p+1)x^py^{q+2}+50(p+2)x^{p+1}y^q$
$\implies\begin{cases}49(q+3)=98(p+1)\\45(q+1)=50(p+2)\end{cases}\implies p=\dfrac52,q=4$

You can verify that $(\mu M)_y=(\mu N)_x$ if you'd like. With the ODE now exact, we have a solution $F(x,y)=C$ such that

$F_x=\mu M$
$F=\displaystyle\int(49y^3+45xy)x^{5/2}y^4\,\mathrm dx$
$F=10x^{9/2}y^5+14x^{7/2}y^7+f(y)$

$F_y=\mu N$
$50x^{9/2}y^4+98x^{7/2}y^6+f'(y)=98x^{7/2}y^2+50x^{9/2}y^4$
$f'(y)=0$
$\implies f(y)=C$

and so the general solution is

$F(x,y)=10x^{9/2}y^5+14x^{7/2}y^7=C$

8 0

3 years ago

James can mow a 1/6 acre and 8 minutes if her rate is constant can James Mow 1 1/2 acre in 1 hour explain

yulyashka [42]

Answer: No

Step-by-step explanation: 1 1/2 divided by 1/6 = 9. Since he said he could mow 1/6 acre in 8 minutes, and he needed to mow 9 x 1/6 acre, we need to multiply 8x9 which equals 72. An hour is 60 minutes so he can't mow 1 1/2 acres in an hour.

5 0

3 years ago