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3 years ago

Each lenght is in metres Calculate DC

Mathematics

1 answer:

Gnom [1K]3 years ago

6 0

Step-by-step explanation:

ED is greater than BC

the line from B to ED ^ (which i drew ) the point it touches ED name it X. so EX will be 2 ( ED-BC)(6-4).

then u have a triangle. EX, XB and EB.

you have length of EX(2) and u have hypotenuse. so u can calculate XB using Pythagoras theorem.

15.1²=2²+XB²

15.1²-2²=XB²

224.01=XB²

XB=14.97

since XB and DC are parallel ( a rectangle is forming XBCD) so DC is also 14.97

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3 years ago

Read 2 more answers

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Answer:

→ First value is 1

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Step-by-step explanation:

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${ \tt{z = 8y - 9 - - - (eqn \: 1)}} \\ \\ { \tt{10x = 8y - 7 - - - (eqn \: 2)}} \\ \\ { \tt{x + y + z = 8 - - - (eqn \: 3)}}$

• from eqn 2, make x the subject:

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${ \tt{ \frac{8y - 7}{10} + y + 8y - 9 = 8}} \\ \\ { \tt{8y - 7 + 10y + 80y - 90 = 80}} \\ \\ { \tt{98y = 177}} \\ \\ { \boxed{ \tt{ \: y = 1.8}}}$

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${ \tt{x = \frac{8(1.8) - 7}{10} }} \\ \\ { \tt{x = \frac{7.4}{10} }} \\ \\ { \boxed{ \tt{ \: x = 0.74 \: }}}$

Rounding to nearest value:

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2 years ago

Each lenght is in metres Calculate DC​

Each lenght is in metres Calculate DC